I WIL A 2.00-kg object traveling east at 20.0 m/s collides with a 3.00-kg object traveling west at 10.0 m/s. After the collision

A 9.0-V battery moves 20 mC of charge through a circuit running from its positive terminal to its negative terminal. How much en

Yuliya22 [3333]

Answer:

The energy delivered is E = 0.18 J

Explanation:

Given,

Battery voltage, V = 9 V

Charge in the circuit, Q = 20 mC

= 20 x 10³ C

Energy supplied in the circuit can be computed as

E = Q V

E = 20 x 10⁻³ x 9

E = 180 x 10⁻³

E equals 0.18 J.

The energy delivered in the circuit is therefore E = 0.18 J

7 0

2 months ago

In order for the ball to be able to make a complete circle around the peg, there must be sufficient speed at the top of its arc

kicyunya [3294]

Answer:

Explanation:

Let T represent the tension in the swing.

At the peak $mg-T=\frac{mv^2}{r}$

where v denotes the velocity needed to maintain the circular motion.

r equals the distance from the rotation point to the center of the ball, which is L+\frac{d}{2} (with d being the ball's diameter).

The threshold velocity can be expressed as $mg-0=\frac{mv^2}{r}$

To determine the velocity at the bottom, we can use energy conservation principles at both the top and bottom positions.

At the top $E_T=mg\times 2L+\frac{mv^2}{2}$

Energy at the bottom $E_b=\frac{mv_0^2}{2}$

By comparing the two states using conservation of energy, we find $v_0^2=4gr+gr$

$v_0^2=5gr$

$v_0=\sqrt{5gr}$

$v_0=\sqrt{5g\left ( \frac{d}{2}+L\right )}$

6 0

3 months ago

Medical cyclotrons need efficient sources of protons to inject into their center. In one kind of ion source, hydrogen atoms (i.e

Keith_Richards [3271]

Answer:

The radius is $r = 4.434 *10^{-5} \ m$

Explanation:

The problem states that

The magnetic field is $B = 90 mT = 90*10^{-3} \ T$

The electron kinetic energy is $KE = 1.4 eV = 1.4 * (1.60*10^{-19}) =2.24*10^{-19} \ J$

In general, for a collision to happen, the centripetal force on the electron in its orbit must equal the magnetic force acting on it

This can be mathematically expressed as

$\frac{mv^2}{r} = qvB$

=> $r = \frac{m* v}{q * B}$

Where m denotes the electron’s mass, which has a value of $m = 9.1 *10^{-31} \ kg$

v signifies the escape velocity, mathematically represented as

$v = \sqrt{\frac{2 * KE}{m} }$

Thus,

$r = \frac{m}{qB} * \sqrt{\frac{2 * KE}{m} }$

applying indices

$r = \frac{\sqrt{2 * KE * m} }{qB}$

substituting these values

$r = \frac{\sqrt{2 * 2.24*10^{-19}* 9.1 *10^{-31}} }{ 1.60 *10^{-19}* 90*10^{-3}}$

$r = 4.434 *10^{-5} \ m$

6 0

2 months ago

Heating a metal from room temperature to pouring temperature in a casting operation depends on all of the following properties e

serg [3582]

Response:

(e) thermal expansion

Clarification:

The density, heat of fusion, and melting temperature of a metal are critical factors to consider when increasing its temperature from room temperature to its melting point. These will dictate the following aspects:

Density: refers to the ratio between a body's mass and the space it occupies in the universe.

Heat of fusion: The enthalpy of fusion or heat of fusion signifies the amount of energy required to cause a mole of an element at its melting point to transition from solid to liquid state, under constant pressure.

Melting temperature is defined as the thermal level at which the phase change from solid to liquid takes place under standard atmospheric pressure.

On the other hand, the dilution of metals only influences the volume they will occupy without affecting the heating process

7 0

2 months ago