Imagine that a chemist is trying to establish whether a piece of rock is from a meteorite that fell from outer space. the rock c

How many moles of nitrogen gas are there in 6.8 liters at room temperature and pressure (293 K and 100 kPa)?

Alekssandra [3086]

Utilize the ideal gas law:

n = PV / RT

P = 100kPa = 100 x 1000 x (9.8 x 10^{-6}) = 0.98 atm
Convert kPa to atm, where 1 Pa = 9.8 x 10^{-6} atm.
T = 293 K
V = 6.8 L
R = 1/12
Substituting all values leads to:
n = 0.272

4 0

3 months ago

What assumption is being made if scientists conclude that aspartic acid was formed by the prebiological synthesis in the passage

lorasvet [2795]

Answer:

A....

Explanation:

8 0

2 months ago

Read 2 more answers

Modern commercial airliners are largely made of aluminum, a light and strong metal. But the fact that aluminum is cheap enough t

lorasvet [2795]

Respuesta:

Un avión fabricado con aluminio puede transportar una mayor cantidad de pasajeros comparado con uno de acero.

Explicación:

La masa total que el avión es capaz de levantar es:

$m_{tot}=m_{fuselage}+m_{passangers}$

Para el aluminio:

$m_{tot}=m_{fus-Al}+m_{pas-Al}$

$m_{fus-Al}=\delta _{Al}*V_{fuselage}$

y

$V_{fuselage}=\frac{\pi *L}{4}*[D^2-(D-e)^2]$

donde:

L es longitud
D es diámetro
e es grosor

$m_{tot}=\delta _{Al}*\frac{\pi *L}{4}*[D^2-(D-e)^2]+m_{pas-Al}$

Para el acero (mismo procedimiento):

$m_{tot}=\delta _{Steel}*\frac{\pi *L}{4}*[D^2-(D-e)^2]+m_{pas-Steel$

Sabiendo que la masa total que el avión puede levantar es constante y que el aluminio tiene una densidad menor que la del acero, podemos afirmar que el avión de aluminio puede levantar un mayor número de pasajeros.

También es posible estimar un peso promedio de los pasajeros para calcular cuántos podría soportar.

5 0

4 months ago

Does the result of the calculation in question 3 justify your original assumption that all of the SCN^- is in the form of FeNCS^

lorasvet [2795]

Fe 3+ + SCN- --> FeSCN 2+

.......Fe 3+.......SCN-.........FeSCN 2+ 
I.......0.04..........0.001.............. 
C........-x...............-x............. 
E.....0.04-x.....0.001-x...........x 

Keq = 203.4 = x / (0.04-x)(0.001-x) 
203.4 = x / (x^2 - 0.041x + 4x10^-5) 
203.4x^2 - 8.34x + 0.00094 = x 
203.4x^2 - 9.34x + 0.00094 = 0 
x = -0.0001M or 0.0458M 
therefore, according to the calculated Keq, all of the SCN- and Fe 3+ would be fully converted into FeSCN 2+

5 0

3 months ago

When drawing the Lewis structure for a molecule, after drawing the skeletal structure and distributing all of the electrons arou

Anarel [2989]

Answer: Rearrange the lone pairs of electrons from the outer atom(s) to create double or triple bonds with the central atom.

Explanation:

7 0

3 months ago