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Bas_tet
1 month ago
14

What assumption is being made if scientists conclude that aspartic acid was formed by the prebiological synthesis in the passage

?
A.Aspartic acid is unstable at temperatures below 150°C.
B.All of the malic acid underwent the dehydration reaction to form fumaric/maleic acid.
C.Compound A and cyanide were available on primitive Earth.
D.The reaction between ammonia and fumaric acid was catalyzed by the presence of water.
Chemistry
2 answers:
lorasvet [2.7K]1 month ago
8 0

Answer:

A....

Explanation:

alisha [2.9K]1 month ago
6 0

Answer:

A. Aspartic acid is unstable at temperatures below 150°C.

Explanation:

Aspartic acid is an amino acid utilized in protein synthesis in living organisms. It possesses an amino group and a carboxylic acid, and the body can produce it. This amino acid is classified as non-essential. It was inferred from the text that aspartic acid cannot remain stable below 150°C. The transamination process involving oxaloacetate in humans results in the production of aspartate, facilitated by the enzyme aminotransferases. Moreover, aspartate plays a significant role in urea synthesis as a metabolite.

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Can one atom in this type of reaction win the "tug of war"? What might happen if it did?
Anarel [2989]
The answer is YES. Polar bonds will indeed form. A polar bond arises when two atoms engage in a covalent bond with unequal distribution of electrons, leading to a molecule exhibiting a slight electrical dipole, with one end carrying a modest positive charge and the other a modest negative charge.
5 0
2 months ago
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Assuming complete dissociation of the solute, how many grams of KNO3 must be added to 275 mL of water to produce a solution that
KiRa [2933]

Answer: The required mass of KNO₃ is, 1.08\times 10^2g

Explanation: Provided,

Molal-freezing-point-depression constant (K_f) for water = 1.86^oC/m

Amount of water = 275 mL

Molar mass of KNO₃ = 101.1 g/mole

First, we need to determine the mass of the water.

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}

Density of water = 1.00 g/mL

\text{Mass of water}=1.00g/mL\times 275mL=275g=0.275kg

Next, we will figure out the mass of KNO₃

Formula utilized:

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of }KNO_3}{\text{Molar mass of }KNO_3\times \text{Mass of water in Kg}}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution = -14.5^oC

\Delta T^o = freezing point of water = 0.0^oC

i = Van't Hoff factor = 2  (for KNO₃ electrolyte)

K_f = freezing point constant for water = 1.86^oC/m

m = molality

Substituting all known values into this equation yields

0.0^oC-(-14.5^oC)=2\times (1.86^oC/m)\times \frac{\text{Mass of }KNO_3}{101.1g/mol\times 0.275kg}

\text{Mass of }KNO_3=108.369g=1.08\times 10^2g

Consequently, the mass of KNO₃ that must be added is, 1.08\times 10^2g

4 0
2 months ago
One type of breathalyzer employs a fuel cell to measure the quantity of alcohol in the breath. When a suspect blows into the bre
Alekssandra [3086]

Response:The ethanol percentage is 0.1093%

Explanation:

As given:

t = time = 10 s

I = current = 320 mA

F = Faraday's constant = 96485.3365 C mol⁻¹

n = number of electrons transferred = 4

Molecular weight of ethanol is 46 g/mol

Question: What is the percent (by volume) of ethanol in the driver's breath, %E =?

First, calculate the ethanol mass:

W=\frac{\frac{46}{4} *0.32*10}{96485.3365} =3.814x10^{-4} g

The moles of ethanol:

n_{ethanol} =3.814x10^{-4} g*\frac{1mol}{46} =8.291x10^{-6} moles

Applying the ideal gas law formula:

V=\frac{nRT}{P}

Here:

T = 26°C = 299 K

P = 1 atm

Substituting in the values:

V=\frac{8.291x10^{-6}*0.082*299 }{1} =2.033x10^{-4} L=0.2033mL

The percentage of ethanol:

E=\frac{0.2033}{186} *100=0.1093%

3 0
2 months ago
A crystallographer measures the horizontal spacing between molecules in a crystal. The spacing is
castortr0y [3046]

Answer: The overall width of a crystal measures 1.65 mm.

Explanation:

Horizontal distance separating the two molecules is 16.5 nm.

Width of the 10^5 molecules:16.5 nm\times 10^5=16.5\times 10^5 nm

1 nm=10^{-6} mm

The overall width of a crystal measured in millimeters=16.5\times 10^5\times 10^{-6} mm=1.65 mm

The overall width of a crystal is 1.65 mm.

7 0
3 months ago
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