684 kcal. One mole of glucose weighs roughly 180g. Given that 1g of glucose releases 3.8 kcal, we calculate for 1 mole of glucose: 180g -> 180g * 3.8 kcal/g = 684 kcal.
Answer:
0.20M of nitric acid
0.00250M of KSCN
Explanation:
In the case of nitric acid, the solution's dilution changes from 10.00mL to 100.00mL, resulting in a 1/10 dilution. Given the original concentration of nitric acid is 2.0M, the updated concentration becomes: 2.0M×(1/10)=0.20M of nitric acid
Similarly, the dilution of KSCN extends from 50.00mL to 100.00mL, equal to a 1/2 dilution. Consequently, the new concentration of KSCN turns out to be:
0.00500M × (1/2) = 0.00250M of KSCN
I hope it aids you!
Answer:
73oc
Explanation:
The change in temperature is calculated as T=123-50=73
Answer:
The final temperature is 80.1 °C
Explanation:
Firstly, we should express the equation clearly and organize the details before conducting the calculations.
