Dane is holding an 8 kilogram box 2 metres above the ground. How much energy is in the box's gravitational potential energy stor

The essential principle for this question is Ohm’s Law: V=IR, I=V/R, R=V/I. Therefore, the answer is (3) Resistance, as it is inversely related to Current (I=V/R).

Answer:

The excess charge is

Explanation:

According to the question, we are informed that

The diameter is

The potential of the surface is

The radius of the sphere is

by plugging in given values

The potential at the surface is mathematically expressed as

Where k is Coulomb's constant with a value

Based on the question stating there are no other charges, Q represents the excess charge

Therefore

inserting the numerical values

Answer: total angular distance = 1700° and 29.7 rad

   the total angular displacement = 0

Explanation:

This is a breakdown of the calculations needed.

The task is to determine both the total angular distance and displacement experienced by the knee.

To calculate the distance traveled by the knee, consider that when squatting, the knee bends 85° to lower, and then another 85° to return to standing (upright). Thus, the cumulative angular movement during the squat totals 170°.

For 10 squats, the knee must undergo 170° motion multiplied by 10, resulting in:

10 * 170° = 1700°

As such, the total angular distance reached is 1700°.

Now converting this to radians since both degree and radian outputs are required:

Since 2π equals 360°, it follows that one degree equates to about 57.3°;

∅ (rad) = ∅ (deg) * 2π/360°

∅ (rad) = 1700° * 2π/360° = 29.7 rad

∅ (rad) = 29.7 rad

For the second part, remember that angular displacement is determined by the angular distance divided by time, leading to a displacement of zero because the knee's ending position is the same as its starting position.

I hope this is helpful!!!!

π

Answer:

The direction in which a vehicle accelerates aligns with its velocity direction. However, the force of acceleration works against the car's speed.

Explanation:

The car’s initial acceleration can be found using:

v = v₀ + a t

a = (v-v₀) t

which assumes the initial speed is zero (v₀ = 0 m/s).

a = v / t

a = 300 / t

The acceleration vector matches the direction of the vehicle's movement.

Upon hitting the wall, a force is exerted in the reverse direction to halt the car, thus this acceleration opposes the vehicle’s speed. However, the module should be much greater since the stopping distance is minimal.