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1 month ago

Which element has the electron configuration [Xe] 6s2 4f14 5d10 6p2?

Chemistry

2 answers:

eduard [2.7K]1 month ago

7 0

The element you are looking for is Pb (Lead). Just check the last orbital on the periodic table to find it!

Tems11 [2.7K]1 month ago

4 0

The answer is Lead (Pb)

Explanation:

The electronic configuration indicates how many electrons are present in a neutral atom. We can determine the total number of electrons by summing all superscripts.

This element is categorized as a p block element since the last electron occupies the p orbital. The closest noble gas is Xenon, which has 54 electrons.

Electrons fill the orbitals according to Aufbau's principle, starting from lower to higher energy levels, resulting in an electronic configuration expressed as:

$[Xe]6s^24f^{14}5d^{10}6p^2$

Total electrons = 54+2+14+10+2= 82

The element with 82 electrons corresponds to atomic number 82, which is lead, represented by the symbol $Pb$

You might be interested in

Draw the structures of two different compounds that have the composition CH3NO2. All three H atoms must remain bonded to the C a

Tems11 [2777]

Answer:

The configurations are illustrated below.

Explanation:

Hydrogen possesses a single electron in its outer shell, carbon has 4, nitrogen has 5, and oxygen holds 6. To achieve an octet (or duet for hydrogen), they require 1, 4, 3, and 2 electrons respectively.

Therefore, each hydrogen atom will share one electron with carbon, while the remaining electron will be shared with nitrogen, maintaining 4 electrons available for sharing. Carbon can form two bonds with both oxygen atoms, expanding its octet; however, this renders it unstable, leading to the formation of resonance structures (redistribution of electrons), and charge formation. One of the oxygen atoms will share only one electron with nitrogen.

The two structures are depicted below.

3 0

2 months ago

What percentage of solar radiation striking a plant is converted into chemical energy?

VMariaS [2998]

1 percent of the solar radiation

3 0

2 months ago

Thallium-207 decays exponentially with a half life of 4.5 minutes. if the initial amount of the isotope was 28 grams, how many g

Anarel [2989]

An exponential decay law is generally expressed as: A = Ao * e ^ (-kt) => A/Ao = e^(-kt) Half-life time => A/Ao = 1/2, and t = 4.5 min => 1/2 = e^(-k*4.5) => ln(2) = 4.5k => k = ln(2) / 4.5 ≈ 0.154. Now substituting k, Ao = 28g, and t = 7 min to determine the remaining grams of Thallium-207 gives: A = Ao e ^ (-kt) = 28 g * e ^( -0.154 * 7) = 9.5 g. Final answer is 9.5 g.

7 0

2 months ago

The nitrogen atom of NH2 would have The nitrogen atom of {\rm NH_2} would have blank electrons around the central nitrogen atom.

Alekssandra [3086]

Answer:

(a) The nitrogen atom in contains $NH_2^-$ 8 electrons surrounding the central nitrogen atom.

(b) The nitrogen atom in has $NH_4^+$ 8 electrons around the central nitrogen atom.

Explanation:

The Lewis dot structure illustrates the connections between atoms within a molecule, additionally showing unpaired electrons present in the molecule.In this structure, valence electrons are represented as 'dots'.

Now we will determine the number of electrons linked to the central nitrogen atom in the specified molecule.

(a) The identified molecule is,

$NH_2^-$ Recognizing that nitrogen has '5' valence electrons while hydrogen has '1', we ascertain the total valence electrons in

= 5 + 2(1) + 1 = 8

According to the Lewis dot structure, this reveals 4 bonding and 4 non-bonding electrons.

$NH_2^-$ From the Lewis structure, we conclude that the nitrogen atom in

has 8 electrons surrounding it.

(b) The identified molecule is, $NH_2^-$

Knowing that nitrogen has '5' valence electrons and hydrogen has '1' valence electron, the total number of valence electrons for $NH_4^+$ = 5 + 4(1) - 1 = 8

In the Lewis dot structure, there are 8 bonding electrons and 0 non-bonding electrons.

This leads us to conclude that the nitrogen atom in

contains 8 electrons surrounding it. $NH_4^+$

$NH_4^+$

Recognizing nitrogen’s '5' valence electrons and hydrogen’s '1' brings the total valence electrons for

= 5 + 3(1) = 8 $NH_3$ Utilizing the Lewis dot structure indicates there are 6 bonding and 2 non-bonding electrons.

According to the Lewis dot structure, we conclude that the nitrogen atom in

has 8 electrons surrounding it.

$NH_2^-$

3 0

1 month ago

A 85.2 g copper bar was heated to 221.32 degrees Celsius and placed in a coffee cup calorimeter containing 4250 mL of water at 2

eduard [2782]

Answer:- 64015 J

Solution: The calorimeter contains 4250 mL of water, which is at a temperature of 22.55 degrees Celsius.

The water's density is 1 gram per mL.

Thus, the mass of water = $4250mL(\frac{1g}{1mL})$ = 4250 grams.

After introducing the hot copper bar, the final temperature of the water reaches 26.15 degrees Celsius.

Thus, $\Delta T$ for the water = 26.15 - 22.55 = 3.60 degrees Celsius.

The specific heat capacity of water is 4.184 $\frac{J}{g.^0C}$ .

To determine the heat absorbed by the water, we can use the following formula:

$q=mc\Delta T$

where q represents heat energy, m refers to mass, and c indicates specific heat.

Now let's substitute the values into the equation to perform the calculations:

$q=4250g*\frac{4.184J}{g.^0C}*3.60^0C$

q = 64015 J

Therefore, the water absorbs 64015 J of heat.

5 0

2 months ago