Answer:
Explanation:
Amount of gold deposited = 0.5 g
Gold's molar mass = 197 g/mol
Time duration, t = 6 hours
= 6 × 3600
= 12600 s
Calculation of moles: mass/molar mass
= 0.5/197
= 0.00254 mole
Assuming
Au --> Au+ + e-
Faraday's constant = 9.65 x 10^4 C mol-1
Charge, Q = 96500 × 0.00254
= 244.924 C
Relation: Q = I × t
Thus, I = 244.924/12600
= 0.011 A
= 11.34 mA.
Answer:
Jari
Explanation:
To determine who is traveling faster, we need to evaluate their gradients. A steeper slope indicates a higher speed.
For Jari's path, starting point is (0, 0) and (6, 7) is another point.
The gradient is the difference in y divided by the difference in x:
Change in y=7-0=7
Change in x=6-0=6
Thus, the slope equals 7/6.
For Jade, her first point is (0, 10) and another is (6, 16).
Change in y=16-10=6
Change in x=6-0=6
Thus, the slope equals 6/6=1.
It's evident that 7/6 exceeds 6/6 or 1, proving Jari is quicker than Jade.
Answer:
155.38424 K
2.2721 kg/m³
Explanation:
= Reservoir pressure = 10 atm
= Reservoir temperature = 300 K
= Exit pressure = 1 atm
= Exit temperature
= Specific gas constant = 287 J/kgK
= Specific heat ratio = 1.4 for air
Assuming isentropic flow
Flow temperature at exit is 155.38424 K
Density at exit can be derived using the ideal gas equation
Flow density at exit measures 2.2721 kg/m³
Answer:
I do not communicate in Spanish
Explanation:
Answer:
A) and B) are valid.
Explanation:
When an object remains at rest, it is indicative that no net force acts upon it.
The downward gravitational force from Earth must be counterbalanced by an upward force of equal magnitude in order to maintain rest.
This upward force is provided by the normal force, which adjusts to satisfy Newton’s 2nd Law and is always perpendicular to the surface supporting the object (in this instance, the ground).
At the molecular level, this normal force comes from the ground's bonded molecules acting like tiny springs, compressed by the object’s molecules, providing an upward restorative force.
Thus, statements A) and B) are true.
