Answer:
Explanation:
The equation used to determine the maximum height of the bowling pin during its trajectory is given by;
H = u²/2g
where u, the initial speed/velocity, equals 10m/s
g stands for gravitational acceleration = 9.81m/s²
Substituting in the values gives us
H = 10²/2(9.81)
H = 100/19.62
Consequently, the highest point of the bowling pin's center of mass is approximately 5.0m.
3.258 m/s Explanation: The spring constant is assumed to be 263 N/m and the displacement of the spring is also assumed to be 0.7 m; the coefficient of friction between blocks is 0.4. The energy stored in the spring is described by . Given the conservation of energy in the system, the speed of the 8 kg block just prior to collision is 3.258 m/s.
