A coaxial cable consists of a thin insulated straight wire carrying a current of 2.00 A surrounded by a cylindrical conductor ca
rrying a current of 3.50 A in the opposite direction. The cylindrical conductor has a radius of 0.420 cm. What is the magnitude of the magnetic field outside of the cylindrical conductor 2.00 cm from the central wire
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Answer:
1 angstrom equals 0.1 nm.
To convert 5000 angstroms: 5000 angstrom = 5000 / 1 × 0.1 nm.
= 500 nm

To express 5000 angstroms in meters: 5000 angstrom = 5000 × 1 × 10^-10.
= 5 × 10^-7 m
Hope this explanation is useful for you.