The refracted angle will be even smaller.
Electric field strength can be calculated as resistivity of copper multiplied by the current density.
where
p= 1.72 x 10^-8 <span>ohm meter
diameter = 2.05mm=.00205 m
current = 2.75 A
</span>First, we determine the current density:
current density = current / cross-sectional area
Calculating the cross-sectional area
cross-sectional area = pi.(d/2)^2;
cross-sectional area = 3.3 006x10-6 m^2
Substituting values gives us
current density = 2.75A/3.3006x 10-6m^2
current density=35.55 x10^2 A/m^2
Thus, electric field strength =1.72 x 10^-8 ohm meter x 35.55 x10^2 A/m^2
Resulting in electric field strength of 46.415 Volts/m.
B. 1 m/s. Converting metric units: 0.3 km equals 300 m, and 5 minutes translates to 300 seconds. Thus, if a seal descends to 300 m in 300 seconds, its diving speed is calculated as distance over time: v = s/t = 300/300 = 1 m/s. Therefore, option B is correct.
Answer:
a) q = 2800 W/m²
b) To = 59.4°C
Explanation:
Given the following parameters:
L = 10 mm
K = 20 W/m·K
T = 30°C
h = 100 W/m²K
Ti = 58°C
a)
Calculating heat flux q:
q = h ΔT
q = 100 x (58 - 30)
q = 2800 W/m²
b)
According to Fourier's law, heat transfer is defined as:
Q = K A ΔT/L
Assuming the outer temperature is To:
To = Ti + qL/K
Substituting the given values:
To = Ti + qL/K
To = 59.4°C
