If 45.5 g of a metal that has a density of 3.65 g/mL is placed in 45.0 mL of water, what is the final volume?

Response: 2. When molecules with different speeds collide, heat is transferred from the faster ones to the slower ones.

Clarification: I hope this was useful!:)

The balanced chemical equation for the neutralization of HCl with is:

Given weight of = 5g

Moles of =

Volume of HCl solution =

Assuming the density of the solution is 1.0 g/mL

Mass of HCl solution = 50 g

Overall mass of the solution = 50 g + 5 g = 55 g

To find the heat of neutralization, we calculate:

Q = m C ΔT

where m equals the mass of the solution = 55 g

C represents the specific heat capacity of the solution = 4.184

ΔT signifies the temperature change = 6.8 K = (6.8 - 273) C = -266.2

The enthalpy of neutralization per mole of

=

Answer:

8 protons, 8 electrons, and 10 neutrons

Explanation:

Answer:

D) NaO2CC6H4CO2K

Explanation:

Water acts as a polar solvent and is known to solvate polar substances. This characteristic allows solute molecules to engage with the solvent, resulting in increased solubility of a molecule as its polarity rises. Consequently, the salt derived from phthalic acid shows greater solubility in water compared to phthalic acid itself. Although both monosodium and monopotassium salts exhibit higher solubility than phthalic acid, the dialkali phthalate salt (NaO2CC6H4CO2K) possesses the highest solubility due to its greater polarity.