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patriot
17 days ago
5

Compound A, C6H8, absorbed 3 equivalents of H2 on catalytic hydrogenation over a Pd/C catalyst to give B (C6H14). On ozonolysis,

compound A gave, among other things, a ketone which was identified as acetone. On treatment with NaNH2 in NH3, followed by addition of iodomethane, compound A gave a new hydrocarbon, C (C7H10). Draw the structure of compound C.
Chemistry
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A chemist is studying the following reaction: NO + NO2 ⇌ N2O3. She places a mixture of NO and NO2 in a sealed container and meas
castortr0y [3046]

Answer:

The forward reaction will keep occurring until all NO or all NO₂ is consumed.

Clarification:

  • According to Le Châtelier's principle, when a system at equilibrium experiences a disturbance from an outside source, the system will adjust to counteract this disturbance and restore equilibrium.

  • Thus, removing the product (N₂O₃) from the system effectively lowers the product concentration, prompting the reaction to shift forward and generate additional product in order to alleviate the strain caused by the removal of N₂O₃.

  • Consequently, the reaction will proceed forward until all of either NO or NO₂ is depleted.

5 0
3 months ago
How many fluorine atoms are present in 5.85 g of c2f4?
eduard [2782]
The molar mass of C2F4 (tetrafluoroethylene) is 100 g/mol. To find the number of moles of C2F4 in the specified quantity,
n = (5.85 g) / (100 g/mol) = 0.0585 mols C2F4
The calculation for the number of molecules per mole is done via the equation,
(0.0585 mols) x (6.022 x 10^23)
Given that each molecule contains 4 F atoms, then,
(0.0585 mols) x (6.022 x 10^23)(4)
= 1.41 x 10^23 atoms of F
4 0
3 months ago
Which statement explains why nuclear waste materials may pose aproblem?(1) They frequently have short half-lives and remain radi
castortr0y [3046]
     Because they often have long half-lives, their radioactive persistence in the environment is lengthy.

Number 4

If you spot any errors in my English, please tell me, since I am not a native speaker.
6 0
2 months ago
Read 2 more answers
In the compound k[co(c2o4)2(h2o)2] (where c2o42– = oxalate) the oxidation number and coordination number of cobalt are, respecti
castortr0y [3046]
Let's represent molecules with symbols as follows:

                   C₂O₄  =  X
and
                    H₂O  =  Y
Then,
                                K [ Co (X)₂ (Y)₂ ]

Since Potassium (K) has an oxidation number of +1

To achieve neutrality, the oxidation number of the coordination sphere needs to equal -1.
Thus,
                                    [ Co (X)₂ (Y)₂ ]  =  -1
Given that,
           the O.N of X is -2
Therefore,
       O.N of (X)₂ equals -4

Additionally,
O.N of H₂O is zero since it remains neutral. Therefore,

                                    [Co - 4 + 0 ]  =  -1
Or,
                                    Co  =  -1 + 4

                                    Co  =  +3

Conclusion:
          The oxidation number for the coordination sphere is -1, and the oxidation state of copper is +3.
6 0
3 months ago
Read 2 more answers
Según la Organización Mundial de la Salud, el nitrato de plata ( densidad = 4.35 g/cc ) es una sustancia con propiedades cáustic
castortr0y [3046]

Respuesta:

737.52 mL de agua

Justificación:

En este escenario, es necesario aplicar la fórmula de molaridad de una solución, que es:

M = moles / V

Donde:

V: Volumen de la solución.

Ya que deseamos determinar la cantidad de agua, en otras palabras, buscamos el volumen del solvente que se utilizó para crear los 800 mL de la disolución.

Una disolución se compone de un soluto y un solvente. El soluto que tenemos es nitrato de plata. Utilizando la fórmula mencionada, calculamos los moles de soluto y luego su masa. Tras eso, calculamos el volumen a partir de la densidad y, al final, determinamos la cantidad de solvente de esta manera:

V ste = Vsol - Vsto

Primero, vamos a calcular los moles de soluto:

moles = M * V

moles = 2 * 0.800 = 1.6 moles

Con este número de moles, obtenemos la masa utilizando el peso molecular que es 169.87 g/mol:

m = moles * PM

m = 1.6 * 169.87 = 271.792 g

Usando el valor de densidad, procederemos a calcular el volumen de soluto utilizado:

d = m/V

V = m/d

V = 271.792 / 4.35

V = 62.48 mL

Por último, la cantidad de agua requerida es:

V agua = 800 - 62.48

V agua = 737.52 mL

8 0
3 months ago
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