Response:
y_red / y_blue = 1.11
Clarification:
To determine the image for each wavelength, we'll utilize the lens maker's equation
1 /f = 1 /o + 1 /i
Where f signifies the focal length, o represents the object distance, and i indicates the image distance
For red light
1 / i = 1 / f - 1 / o
1 / i_red = 1 / f_red - 1 / o
1 / i_red = 1 / 19.57 - 1/30
1 / i_red = 1.776 10-2
i_red = 56.29 cm
For blue light
1 / i_blue = 1 / f_blue - 1 / o
1 / i_blue = 1 / 18.87 - 1/30
1 / i_blue = 1.966 10-2
i_blue = 50.863 cm
Next, we will compute the magnification ratio
m = y ’/ h = - i / o
y ’= - h i / o
For red light
y_red ’= - 5 56.29 / 30
y_red ’= - 9.3816 cm
For blue light
y_blue ’= 5 50.863 / 30
y_blue ’= - 8.47716 cm
The ratio of the heights of both images is
y_red ’/ y_blue’ = 9.3816 / 8.47716
y_red / y_blue = 1.107
y_red / y_blue = 1.11
Answer: The correct choice is (d) 
Explanation:
This analysis assumes that the heat supplied by the hot body matches the heat absorbed by the cold body.
where,
= the specific heat capacity of copper = 
= the specific heat capacity of water = 
= the mass of copper = 120 g
= the mass of water = 300 g
= the final temperature of the mixture = 
= the initial temperature of copper =?
= the initial temperature of water = 
Using the provided values in the equation yields:
Thus, the temperature of the kiln is approximately
Answer:
a. 8.33 x 10 ⁻⁶ Pa
b. 8.19 x 10 ⁻¹¹ atm
c. 1.65 x 10 ⁻¹⁰ atm
d. 2.778 x 10 ⁻¹⁴ kg / m²
Explanation:
Provided Data:
a.
I = 2500 W / m², us = 3.0 x 10 ⁸ m /s
P rad = I / us
P rad = 2500 W / m² / 3.0 x 10 ⁸ m/s
P rad = 8.33 x 10 ⁻⁶ Pa
b.
P rad = 8.33 x 10 ⁻⁶ Pa *[ 9.8 x 10 ⁻⁶ atm / 1 Pa ]
P rad = 8.19 x 10 ⁻¹¹ atm
c.
P rad = 2 * I / us = ( 2 * 2500 w / m²) / [ 3.0 x 10 ⁸ m /s ]
P rad = 1.67 x 10 ⁻⁵ Pa
P₁ = 1.013 x 10 ⁵ Pa /atm
P rad = 1.67 x 10 ⁻⁵ Pa / 1.013 x 10 ⁵ Pa /atm = 1.65 x 10 ⁻¹⁰ atm
d.
P rad = I / us
ΔP / Δt = I / C² = [ 2500 w / m² ] / ( 3.0 x 10 ⁸ m/s)²
ΔP / Δt = 2.778 x 10 ⁻¹⁴ kg / m²
