Two vectors A⃗ and B⃗ are at right angles to each other. The magnitude of A⃗ is 4.00. What should be the length of B⃗ so that th

Result:

1.60 g

Elucidation:

Based on the attached document:

we can infer that:

The distance covered in 2 seconds will be:

x = vt

x = 20 m/s × 2 s

x = 40 m

The segment corresponds to a quarter of a circle with radius r,

therefore, if 2 πr = 4 x

Then the radius (r) can be calculated as:

r = 25.5 m

Centripetal acceleration can be expressed as:

thus;

a = 15.7 m/s²

The acceleration magnitude suffered by your passengers in relation to the acceleration due to gravity can be calculated using:

∴ The acceleration magnitude experienced by your passengers while turning = 1.60 g

Response:

3.5 N

Reasoning:

Taking the 0 cm position as the pivot point, to achieve balance, the total moment calculated around this point must equal zero. We will analyze the moment generated at each point, moving from 0 to 100 cm:

- Tension from the string at the 0 cm mark is 0, since the moment arm is nonexistent.

- A 2 N weight at the 10 cm point creates a moment of 20 Ncm moving clockwise.

- Another 2 N weight at the 50 cm position produces a moment of 100 Ncm also clockwise.

- The weight of the 1 N stick located at its center of mass (50 cm) has a moment of 50 Ncm, clockwise.

- A 3 N weight at the 60 cm position generates a moment of 180 Ncm, clockwise.

- The tension T (N) from the string at the 100 cm end contributes a moment of 100T Ncm, moving counter-clockwise.

Total clockwise moments = 20 + 100 + 50 + 180 = 350 Ncm.

Total counter-clockwise moment = 100T.

To achieve balance, we set 100 T = 350, leading to T = 350 / 100 = 3.5 N.