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Hunter-Best
3 months ago
9

How many moles are there in 20.0 grams of FeCl3?

Chemistry
1 answer:
lions [2.9K]3 months ago
6 0

Explanation:

The number of moles present is approximately 0.1168258310995 moles. Hope this helps!

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In basic solution, se2− and so32− ions react spontaneously and e o cell = 0.35 v. (a) write the balanced half-reactions for this
lions [2927]

(a)   Write the balanced half-reactions for the overall process:

Oxidation: Se^2- (aq) → Se (s) + 2e-

Reduction: 2So3^2- (aq) + 3H2O (l) + 4e- → S2O3^2- + 6OH- (aq)

(b)   Assuming E sulfite is 0.57 V, compute E selenium:

E anode = E cathode – E cell

= -0.57 – 0.35

= -.092

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3 months ago
What assumption is being made if scientists conclude that aspartic acid was formed by the prebiological synthesis in the passage
lorasvet [2795]

Answer:

A....

Explanation:

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2 months ago
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A piece of iron metal is heated to 155 degrees C and placed into a calorimeter that contains 50.0 mL of water at 18.7 degrees C.
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4 months ago
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Is N2 + H2 →NH4 a balanced chemical equation? Is it obeying the law of conservation of matter?
eduard [2782]
The response is:

No, the equation is not balanced. Neither the Nitrogen (N) nor the Hydrogen (H) are in balance!

Here's the reasoning:

⓵ A properly balanced chemical equation means that the quantity of atoms on the reactants side matches that on the products side.

→ The equation lacks balance because there are 2 Nitrogen atoms and 2 Hydrogen atoms on the reactants side. In contrast, on the products side, there is only 1 Nitrogen atom and 4 Hydrogen atoms. Thus, the number of atoms on each side is not consistent!

Hopefully, this clarification is helpful; feel free to reach out if you have any further questions! ☻
8 0
3 months ago
The metallic radius of a potassium atom is 231 pm. What is the volume of a potassium atom in cubic meters?
Anarel [2989]
1 pm equals 10^{-10} cm. Therefore, 230 pm can be converted to 2.3 × 10^{-8} cm. Atoms are spherical in shape, and the volume of a sphere can be calculated using the formula 4/3πr³. Consequently, the atom's volume is calculated as 4/3π(2.3 × 10^{-8})³. Evaluating this gives 4/3 × (3.142 × 12.167 × 10^{-24}), which simplifies to approximately 5.096 × 10^{-23} cm³. Since 1 m³ is equal to 1,000,000 cm³, we find that the volume of the atom is 5.096 × 10^{-29} m³.
8 0
4 months ago
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