Answer:
The empirical formula is: C₂H₃O
Explanation:
The empirical formula, often referred to as the “minimum formula,” provides the simplest way to represent a chemical compound, illustrating both the present elements and their minimum integer ratios in terms of atoms.
The mass percentage composition indicates the proportion by mass of each element in a compound.
Using 100 g of the compound as a reference, the percentage can be expressed in grams. Thus, presuming 100 g of the compound consists of 53.46 g of C, 6.98 g of H, and 39.56 g of O.
Considering the molecular masses of each component, one can derive the number of relative atoms for each element:
C: 
H:
O:
Subsequently, divide each value by the smallest one:
C: 
H:
O:
Approximating decimals to the nearest integer gives:
C: 2
H: 3
O: 1
Therefore the empirical formula is: C₂H₃O
The total number of particles present in 12.7 moles of the compound owned by Jessica is 7.65 x10^24 particles of the compound (response E)
Calculation Steps
The total number of particles is determined through Avogadro's Principle constant.
- This principle states that Avogadro's 1 mole equals 6.02 x10^23 particles
So, how many particles correspond to 12.7 moles of the compound? particles\
By applying cross multiplication, the formula yields: particles of the compound= [12.7 moles x (6.02 x 10^23)] / 1 mole
= 7.65 x 10^24 particles of the compound (response E)
moles cancels each other out.
5.451 X 10³ kg of sodium carbonate is required to neutralize 5.04×10³ kg of sulfuric acid solution.
Explanation:
- Sodium carbonate neutralizes sulfuric acid (H₂SO₄). This compound is derived from a strong base (NaOH) and a weak acid (H₂CO₃). The chemical equation for this neutralization process is represented as:
Na₂CO₃ + H₂SO₄ ----> Na₂SO₄ + H₂CO₃
- The balanced equation indicates that one mole of Na₂CO₃ is needed to neutralize one mole of H₂SO₄.
- Molar mass of Na₂CO₃= 106 g/mol = 0.106 kg/mol, while Molar mass of H₂SO₄= 98 g/mol = 0.098 kg/mol.
- To neutralize 0.098 kg of H₂SO₄, the required Na₂CO₃ is 0.106 kg, thus, to neutralize 5.04×10³ kg of H₂SO₄, Na₂CO₃ needed is 5.451 X 10³ kg.
Elemental zinc replaces copper
Explanation:
During this reaction, the zinc added to the copper sulfate solution has replaced the copper present in the compound.
This process is known as a single displacement reaction.
Zn + CuSO₄ → ZnSO₄ + Cu
This represents the reaction in the recycling process.
The reaction is influenced by the elements' positions within the reactivity series of metals.
- In a single displacement reaction, an element higher in the reactivity series displaces one that is lower.
- Zinc ranks above copper in this series, allowing it to react with sulfate.
- Consequently, copper is pushed out as a solid product in the solution.
- Elements positioned higher in this series exhibit greater reactivity
learn more:
Chemical reaction
The formula for Molarity is given by:
M = moles / V
To isolate V,
V = moles / M ------------------(1)
Moles can also be calculated as:
moles = mass / M.mass -------------(2)
Substituting the value of moles from equation 2 into equation 1 yields:
V = (mass / M.mass) / M
Plugging in the numbers gives:
V = (45 g / 164 g/mol) / 1.3 mol/dm³
V = 0.21 dm³.
