a crowbar of 2 meter is used to lift an object of 800N if the effort arm is 160cm , calculste the effort applied

To calculate acceleration, divide the force by mass: F = m × a results in 3.63 = 18.15 × a leading to 3.63 = 18.15a, which gives a = 3.63/18.15, equating to a = 0.2 m/s².

The time required for the water balloon to reach the ground is given as

Here we understand that

Now applying the earlier mentioned formula

Now in the same time frame, we can conclude the distance covered will be

Thus, it will land at a distance of 15.7 m from where it started

Arginine is classified as a basic amino acid since it has two amino groups alongside a single acid group. At a low pH level, all ionizable groups are protonated. As the pH rises slightly, the acid group loses its proton. When the pH increases further, one of the amino groups also loses a proton. At considerably high pH levels, none of the ionizable groups remain protonated.

Pkas

<span> <span><span> <span> pka1 = 1.82 </span> <span> pka2 = 8.99 </span> <span> pka3 = 12.48 </span> </span> </span></span> Thus, 9.20 is above the second pKa and below the third pKa. This indicates that the acid has already lost its proton, as has one of the amino groups, while the second amino group remains protonated. When an acid is not protonated, it carries a negative charge. An unprotonated amino group is neutral, whereas when protonated, the amino group bears a positive charge. Therefore, this amino acid exhibits one positive charge (from one of the amino groups) and one negative charge (from the acid), resulting in an overall neutral charge.

Answer:

Consequently, the temperature difference across the material will be

Explanation:

In this case, we apply the Fourier Law of heat conduction expressed by the following equation:

  (1)

Where k = thermal conductivity = 0.2 W/ mK

A= 1m^2 denotes the cross-sectional area

Q= 3KW signifies the heat transfer rate

is the temperature difference we need to determine

represents the thickness of the material

To isolate from equation (1), we obtain:

Initially, we convert 3KW to W, resulting in:

With all variables accounted for, we can substitute and calculate:

Thus, the temperature difference across the material will be