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Ludmilka
6 days ago
9

"What will the pressure inside the container become if the piston is moved to the 1.60 L mark while the temperature of the gas i

s kept constant?"
Physics
1 answer:
Softa [913]6 days ago
5 0

Esta pregunta está incompleta, la pregunta completa es;

La figura muestra un recipiente sellado en la parte superior por un pistón móvil. Dentro del recipiente hay un gas ideal a 1.00 atm. 20.0°C y 1.00 L.

"¿Cuál será la presión dentro del recipiente si el pistón se mueve hasta la marca de 1.60 L mientras se mantiene constante la temperatura del gas?"

Answer:

la presión dentro del recipiente será 0.625 atm si el pistón se mueve hasta la marca de 1.60 L manteniendo constante la temperatura del gas

Explicación:

Dado que;

P₁ = 1.00 atm

P₂ =?

V₁ = 1 L

V₂ = 1.60 L

la temperatura del gas se mantiene constante

sabemos que;

P₁V₁ = P₂V₂

por lo que hacemos la sustitución

1 × 1 = P₂ × 1.60

P₂ = 1 / 1.60

P₂ = 0.625 atm

Por lo tanto, la presión dentro del recipiente será 0.625 atm si el pistón se mueve hasta la marca de 1.60 L mientras la temperatura del gas se mantiene constante

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An airplane pilot wishes to fly directly westward. According to the weather bureau, a wind of 75.0 km/hour is blowing southward.
Softa [913]

Answer:

The plane's speed in relation to the ground is 300.79 km/h.

Explanation:

Provided details include:

Wind speed = 75.0 km/hr

Plane's airspeed = 310 km/hr

Next, we must find the ground speed of the plane

Calculating the angle

Using the angle formula

\sin\theta=\dfrac{v'}{v}

Where v' represents the wind speed

v represents the plane's speed

We will substitute the values into the formula

\sin\theta=\dfrac{75}{310}

\theta=\sin^{-1}(\dfrac{75}{310})

\theta=14.0^{\circ}

Now, we must find the resultant speed

Using the resultant speed formula

\cos\theta=\dfrac{v''}{v}

Insert the values into the formula

\cos14=\dfrac{v''}{310}

v''=\cos14\times310

v''=300.79\ km/h

Consequently, the plane's speed in relation to the ground equals 300.79 km/h.

6 0
7 days ago
A small mass m is tied to a string of length L and is whirled in vertical circular motion. The speed of the mass v is such that
serg [1198]

Response:

(mv^2/R)/(mg)=1/2

v^2=R/2g

7 0
6 days ago
A uniform magnetic field makes an angle of 30o with the z axis. If the magnetic flux through a 1.0 m2 portion of the xy plane is
Yuliya22 [1153]

Response:

(b) 10 Wb

Clarification:

Given;

angle of the magnetic field, θ = 30°

initial area of the plane, A₁ = 1 m²

initial magnetic flux through the plane, Φ₁ = 5.0 Wb

The equation for magnetic flux is;

Φ = BACosθ

where;

B denotes the magnetic field strength

A represents the area of the plane

θ is the inclination angle

Φ₁ = BA₁Cosθ

5 = B(1 x cos30)

B = 5/(cos30)

B = 5.7735 T

Next, calculate the magnetic flux through a 2.0 m² section of the same plane:

Φ₂ = BA₂Cosθ

Φ₂ = 5.7735 x 2 x cos30

Φ₂ = 10 Wb

<pHence, the magnetic flux through a 2.0 m² area of the same plane is 10 Wb.

Option "b"

3 0
5 days ago
What is the sources of error and suggestion on how to overcome it in the hooke's law experiment?
Yuliya22 [1153]
In the study of physics, Hooke's law can be expressed as:

F = kx

This law indicates that the spring force F is proportional to the extension x, with k being the spring constant.

In experiments, this is often examined using the setup illustrated in the included figure. The spring is tested, and a known weight is applied underneath it. This weight exerts a gravitational pull, essentially its weight, on the spring. While the spring elongates, the displacement can be measured using a ruler.

Several potential errors can arise during this experiment. Firstly, the person's measurement reading may be faulty. Digital scales offer greater accuracy as they reduce human error, while ruler readings can be subjective, especially if not viewed at eye level. Additionally, the object's weight may be inaccurately measured if the scale is untrustworthy. Lastly, the measuring equipment may not be correctly calibrated.

6 0
22 hours ago
Imagine you are a water molecule, carbon atom, or nitrogen atom that is inside a cow. Write a brief explanation of how you got f
Maru [1056]

Answer:

Explanation:

Each of the processes connected to these molecules varies.

For instance, water that has accumulated in the atmosphere returns to the ground as rain. Cows utilize this water from local water sources. This represents one method in which water transitions from the atmosphere to the cow's body.

Regarding carbon and nitrogen, the air inhaled by cows contains nitrogen, oxygen, carbon dioxide, and other gases. These molecules enter the cow through respiration.

6 0
2 days ago
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