Lynn rubs a balloon with a piece of wool, which causes the balloon to pick up some of the electric charges from the wool. Lynn t

hen observes that the balloon temporarily sticks to a wall. After several seconds, the balloon falls to the ground. Which best describes the forces in this scenario?
The strong force causes the balloon to stick to the wall, and the weak force causes the balloon to fall to the ground.
The weak force causes the balloon to stick to the wall, and the strong force causes the balloon to fall to the ground.
The electromagnetic force causes the balloon to stick to the wall, and gravitational force causes the balloon to fall to the ground.
Gravitational force causes the balloon to stick to the wall, and electromagnetic force causes the balloon to fall to the ground.

Physics

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a) 3.56 x 10^22 N. b) 3.56 x 10^22 N. The sun’s mass is M = 2 x 10^30 kg, while the Earth's mass is m = 6 x 10^24 kg, with a distance of R = 1.5 x 10^11 m separating them. Applying Newton's law for gravitational force F = G (mM / R²), where G = 6.67 × 10^-11 m^3 kg^-1 s^-2 gives us F = 3.56 x 10^22 N. A) The gravitational force by the sun on Earth equates to the force exerted by Earth on the sun, which is also 3.56 x 10^22 N.

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A mass attached to a 66.4 cm long string starts from rest and is rotated 36.6 rev in1 min before reaching a final angular speed.

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Answer:

0.128 rad/s², 7.66 rad/s

Explanation:

length, l = 66.4 cm

initial angular velocity, ωo = 0 rad/s

Let ω represent the final angular velocity.

Let α denote the angular acceleration.

number of revolutions, n = 36.6

time taken, t = 1 min = 60 seconds

Angle rotated, θ = 2πn = 2 x 3.14 x 36.6 = 229.85 rad

Apply the second equation of motion for angular dynamics

$\theta =\omega _{0}t+\frac{1}{2}\alpha t^{2}$

229.85 = 0 + 0.5 x α x 60 x 60

α = 0.128 rad/s²

Utilize the first equation of motion

ω = ωo + αt

ω = 0 + 0.128 x 60

ω = 7.66 rad/s

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