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vlabodo
3 months ago
5

A constant torque of 260 Nm acts on a flywheel. If the flywheel makes 25 complete revolutions in 2 minutes, what is the power ex

erted by the torque?
Physics
2 answers:
ValentinkaMS [3.4K]3 months ago
7 0
 I don't know that; sorry, I should just be removed from here.
Softa [3K]3 months ago
6 0
The power resulting from the torque is 340.34 W. Explanation: The angular speed can be calculated as ω = (25/2)(rev/min)(2π rad/rev)(min/60s) = 1.308 rad/s. The torque applied is T = 260 Nm. The power can be found using P = T ω, therefore P = (260)(1.308) leads to P = 340.34 W, which indicates the power exerted by the torque of 260 Nm.
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If a steady-state heat transfer rate of 3 kW is conducted through a section of insulating material 1.0 m2 in cross section and 2
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Answer:

\Delta T = \frac{3000 W *0.025 m}{1 m^2 (0.2 \frac{W}{mK})}= 375 K

Consequently, the temperature difference across the material will be \Delta T = 375 K

Explanation:

In this case, we apply the Fourier Law of heat conduction expressed by the following equation:

Q = -kA \frac{\Delta T}{\Delta x}   (1)

Where k = thermal conductivity = 0.2 W/ mK

A= 1m^2 denotes the cross-sectional area

Q= 3KW signifies the heat transfer rate

\Delta T is the temperature difference we need to determine

represents the thickness of the material\Delta x=2.5 cm =0.025 m

To isolate \Delta T from equation (1), we obtain:

\Delta T =\frac{Q \Delta x}{Ak}

Initially, we convert 3KW to W, resulting in:

Q= 3 KW* \frac{1000W}{1 Kw}= 3000 W

With all variables accounted for, we can substitute and calculate:

\Delta T = \frac{3000 W *0.025 m}{1 m^2 (0.2 \frac{W}{mK})}= 375 K

Thus, the temperature difference across the material will be \Delta T = 375 K

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2 months ago
Uzupełnij zdania właściwymi sformułowaniami. Wyobraź sobie, że między linę a siodełko karuzeli łańcuchowej wmontowany jest siłom
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Explanation:

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