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vlabodo
1 month ago
5

A constant torque of 260 Nm acts on a flywheel. If the flywheel makes 25 complete revolutions in 2 minutes, what is the power ex

erted by the torque?
Physics
2 answers:
ValentinkaMS [3.4K]1 month ago
7 0
 I don't know that; sorry, I should just be removed from here.
Softa [3K]1 month ago
6 0
The power resulting from the torque is 340.34 W. Explanation: The angular speed can be calculated as ω = (25/2)(rev/min)(2π rad/rev)(min/60s) = 1.308 rad/s. The torque applied is T = 260 Nm. The power can be found using P = T ω, therefore P = (260)(1.308) leads to P = 340.34 W, which indicates the power exerted by the torque of 260 Nm.
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During the construction of an office building, a hammer is accidentally dropped from a height of 784 ft. the distance (in feet)
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2 months ago
Steve and Elsie are camping in the desert, but have decided to part ways. Steve heads north, at 8 AM, and walks steadily at 2 mi
Keith_Richards [3271]

Answer:

2.57 hours

Explanation:

Let t (in hours) represent the time it takes for Elsie to walk until they are separated by 25 miles. Since Steve starts 2 hours earlier, his time will be t + 2.

The distance covered by Steve heading north is s_s = 2(t + 2)

The distance Elsie travels heading west is s_e = 2.5t

The separation between Steve and Elsie is

\sqrt{s_s^2 + s_e^2} = \sqrt{(2(t+2))^2 + (2.5t)^2} = 25

We can solve for t by squaring both sides.

(2(t+2))^2 + (2.5t)^2 = 25^2 = 625

4(t+2)^2 + 6.25t^2 = 625

4(t^2 + 4t + 4) + 6.25t^2 = 625

10.25t^2 + 16t - 609 = 0

t= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

t= \frac{-16\pm \sqrt{(16)^2 - 4*(10.25)*(-109)}}{2*(10.25)}

t= \frac{-16\pm68.74}{20.5}

Therefore, t = 2.57 or t = -4.13.

Since t cannot be negative, we select t = 2.57 hours.

8 0
2 months ago
A 100-watt light bulb radiates energy at a rate of 100 J/s. (The watt, a unit of power or energy over time, is defined as 1 J/s.
Keith_Richards [3271]

Answer:

2.64\times 10^{20} The number of photons emitted each second is

Explanation:

Let 'n' stand for the quantity of photons released by the bulb.

Provided Information:

The bulb radiates energy at a rate of 100 J per second (E).

Wavelength of emitted light is (λ) = 525 nm = 525\times 10^{-9}\ m

The energy of a photon is calculated by:

Where,

E_0=\frac{hc}{\lambda}

Now, if we have 'n' photons, the total energy is equivalent to the energy of a single photon multiplied by the count of photons. Thus,

h\to Planck's\ constant=6.626\times 10^{-34}\ Js\\\\c\to Speed\ of \ light=3\times 10^{8}\ m/s

To express in terms of 'n', we find:

E=nE_0\\\\E=\frac{nhc}{\lambda}

Insert the provided values and solve for 'n'. The resulting calculation yields

n=\frac{E\lambda}{hc}

Consequently,

photons are discharged every second.n=\frac{100\times 525\times 10^{-9}}{6.626\times 10^{-34}\times 3\times 10^{8}}\\\\n=2.64\times 10^{20}

2.64\times 10^{20}

8 0
1 month ago
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