Greetings,
The number of lone pairs of electrons in a C2O molecule is...
4
Each Oxygen atom forms two bonds with Carbon.
I hope this was useful!
-Char
Answer: Option (a) is the correct answer.
Explanation:
Under conditions of low pressure and high temperature, gas molecules exhibit negligible attractions or repulsions among themselves. Hence, gases behave ideally in these scenarios.
Conversely, at low temperatures, there is a reduction in the kinetic energy of gas molecules, while high pressure compels the molecules to be closer together.
Thus, attractive forces emerge between molecules in conditions of low temperature and high pressure, causing gases to be termed real gases.
Therefore, we conclude that the ideal gas law becomes less accurate when pressure increases and temperature decreases.
1) Calcium carbonate comprises 40.0% calcium by weight.
M(CaCO₃)=100.1 g/mol
M(Ca)=40.1 g/mol
w(Ca)=40.1/100.1=0.400 (which is 40.0%)!
2) The mass fraction mentioned is superfluous information.
3) The resulting solution is:
m(Ca)=1.2 g
m(CaCO₃)=M(CaCO₃)*m(Ca)/M(Ca)
m(CaCO₃)=100.1g/mol*1.2g/40.1g/mol=3.0 g
Answer:
180.56 kilojoules of heat energy is extracted when 1.00 kg of freon-11 evaporates.
Explanation:
The molar mass of freon-11 is 137.35 g/mol
The enthalpy of vaporization for freon-11 is 24.8 kJ/mol at its normal boiling point of 24°C. Given that,
Mass of freon-11 evaporated = 1.00 kg = 1000 g
Moles of freon-11 evaporated can be calculated as
The energy removed in the form of heat when 1.00 kg of freon-11 vaporizes is:
