The direction of the arrow indicates that the bond involving the chlorine atom and the fluorine atom is nonpolar. The fluorine atom pulls the electrons in the bond with greater strength, resulting in the chlorine atom being a little positive.
Explanation:
- The bond formed between chlorine and fluorine displays nonpolar characteristics because both atoms contribute an equal share of electrons within the bond. Examples such as H2, F2, and Cl2 illustrate this concept well.
- Both chlorine and fluorine are electronegative elements, yet fluorine resides above chlorine in the periodic table. Fluorine's position above chlorine gives it a somewhat higher electronegativity compared to chlorine. This explains why fluorine molecules attract electrons more efficiently than chlorine atoms, resulting in chlorine exhibiting a slight positive charge in bonds between Cl and F.
E = mc²
where E = energy produced
m = mass of the nucleus
C = speed of light
m = 9.106 x 10⁻³ x 1.67 x 10⁻²⁷ kg
C = 3 x 10⁸ m/s, thus C² = 9 x 10¹⁶
E = 1.37 x 10⁻¹² J
To calculate the moles of MgSO4.7H2O, we find the molar mass equals 246, thus moles = 32 / 246 = 0.13 moles. Upon heating, all 7 H2O from one molecule will evaporate. The total moles of H2O present amount to 7 x 0.13 = 0.91, and the mass of that H2O is 0.91 x 18 = 16.38g. Therefore, the mass of the anhydrous MgSO4 that remains is 32 - 16.38 = 15.62 g.
To solve this problem, an equation that encompasses all this information is required. The Ideal Gas Law, represented as PV=nRT, is the one we'll utilize. However, it's necessary to convert some figures into alternate units for accurate calculations. We will convert Celsius to Kelvin and Pascals to atmospheres (1 atm = 101300 Pa), allowing us to substitute and simplify:
PV = nRT
(0.1185 atm)V = (17 mol)(0.0821 L•atm/K•mol)(307.15 K)
0.1185V = 428.689
V = 3617.63 L
Since the inquiry requires the volume in cubic meters, recall that 1 m^3 is equal to 1,000 liters. Therefore, dividing the obtained value by 1,000 will yield the answer.
Thus, the tank will hold a volume of B, 3.62 m^3.
I hope this clarifies the question!
