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2 months ago

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In t-ball, young players use a bat to hit a stationary ball off a stand. The 140 g ball has about the same mass as a baseball, b

ut it is larger and softer. In one hit, the ball leaves the bat at 12 m/s after being in contact with the bat for 2.0 ms . Assume constant acceleration during the hit.

1 answer:

Yuliya22 [3.3K]2 months ago

3 0

Question is missing. Found the following on Google:

"Part A: What is the acceleration of the ball? Please provide your answer with two significant digits and include the units.

Part B:

What is the net force acting on the ball during the hit? Provide your answer with two significant figures and the units.

Solution:

A) $6000 m/s^2$

The ball's acceleration is calculated as:

$a=\frac{v-u}{t}$

where

v = 12 m/s (final velocity)

u = 0 (initial velocity since the ball was still)

t = 2.0 ms = 0.002 s (contact time)

Substituting these values,

$a=\frac{12-0}{0.002}=6.0 \cdot 10^3 m/s^2$

B) $8.4\cdot 10^2 N$

Using Newton's second law, the force on the ball is:

$F=ma$

where

m = 140 g = 0.14 kg (mass of the ball)

$a=6.0\cdot 10^3 m/s^2$ is the acceleration

Substituting values,

$F=(0.14)(6.0\cdot 10^3)=8.4\cdot 10^2 N$

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