80 g. Explanation: In the metal alloy, the weight percent of antimony can be determined using the formula wt% = (mass of compound/mass of alloy)×100. Since we have 16% = (grams of antimony / grams of alloy)×100, simplifying gives us 0.16 = grams of antimony / grams of alloy, and therefore if the alloy is 500 g, it leads us to the conclusion that the weight of antimony is 80 g.
The Chemistry Regents is one of the four science Regents exams. The remaining three are Earth Science, Living Environment, and Physics. Passing at least one of these four exams is a requirement for high school graduation.
Answer:
Explanation:
Considering the reaction: 2X + 3Y = 3Z, combining 2.00 moles of X with 2.00 moles of Y results in the production of 1.75 moles of Z.
2 mol 2 mol 1.75 mol
2X + 3Y = 3Z
2 mol is required with 3 mol to yield 3 mol.
3 mol Z / 3 mol Y = 1 to 1
should yield 2 mol Z
1.75 / 2 = 87.5 % production yield
Response:
4.5 m³
Resolution:
The statement indicates the presence of two blocks on a lid of a container with a volume of 9 m³. The lid's weight is equal to that of the two blocks. Thus, there were initially four blocks (or 4 atm pressure) acting on a volume of 9 m³.
After adding four additional blocks on the lid, the pressure rises from 4 atm to 8 atm (2 atm from the lid, 2 atm from the original blocks, and 4 atm from the new blocks).
Hence, The data established is,
P₁ = 4 atm
V₁ = 9 m³
P₂ = 8 atm
V₂ =?
Using Boyle's Law,
P₁ V₁ = P₂ V₂
Resolving for V₂,
V₂ = P₁ V₁ / P₂
Substituting values yields:
V₂ = (4 atm × 9 m³) ÷ 8 atm
V₂ = 4.5 m³
Answer:
To break a single I-I bond, the wavelength of light required is 7.92 × 10⁻⁷ m
Explanation:
The energy needed to break one mole of iodine-iodine single bonds is 151 KJ
The energy necessary to rupture one iodine-iodine bond is calculated as (151 KJ/mol) / 6.02 × 10²³/mol = 2.51 × 10⁻²² KJ
or
2.51 × 10⁻¹⁹ J
Formula:
E = hc / λ
Where h is Planck's constant = 6.626 × 10⁻³⁴ js
c is the speed of light = 3 × 10⁸ m/s
λ
= wavelength
Solution:
E = hc / λ
λ = hc / E
λ = (6.626 × 10⁻³⁴ js × 3 × 10⁸ m/s ) / 2.51 × 10⁻¹⁹ J
λ = 19.878 × 10⁻²⁶ j.m / 2.51 × 10⁻¹⁹ J
λ = 7.92 × 10⁻⁷ m
