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erik
1 month ago
10

The researcher performed a follow-up experiment to measure the rate of oxygen consumption by muscle and brain cells. Predict the

effect of the MT - ND5 mutation on the rate of oxygen consumption in muscle and brain cells. Justify your prediction. The researcher had hypothesized that the addition of the vitamin that is similar in structure to NADH would increase the activity of the mutated NADH dehydrogenase enzyme in individuals with the disorder. Explain how the vitamin most likely increased the activity of the enzyme.
Chemistry
2 answers:
Alekssandra [3K]1 month ago
0 0

Answer:

Mitochondria are plentiful in mammalian cells, with their proportions varying across different tissues, from less than 1% in white blood cells to as high as 35% in heart muscle cells. It is essential to understand that mitochondria are not static structures but instead form a dynamic network that frequently undergoes processes of fission and fusion. In skeletal muscle, they exist as part of a reticular membrane network. The two subpopulations, subsarcolemmal (SS) and intermyofibrillar (IMF) mitochondria, occupy different subcellular regions and exhibit slight differences in their biochemical and functional characteristics tied to their anatomical context. The SS mitochondria are positioned just beneath the sarcolemma, while IMF mitochondria are found closely associated with myofibrils. Their distinct properties likely play a role in their adaptability. SS mitochondria make up about 10-15% of the total mitochondrial volume and are believed to be more adaptable than their IMF counterparts, despite the latter displaying higher levels of protein synthesis, enzyme activity, and respiration (1).

Explanation:

Alekssandra [3K]1 month ago
0 0

Answer:

The rate at which muscle and brain cells consume oxygen is expected to decline. The MT-ND5 mutation leads to a buildup of lactic acid resulting from glycolysis not progressing to the Krebs cycle; rather, it ends up in fermentation. Consequently, since the Krebs cycle is not being utilized, oxygen consumption ceases.

Explanation:

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You are asked to go into the lab and prepare an acetic acid - sodium acetate buffer solution with a ph of 4.00  0.02. what mola
castortr0y [3046]
Greetings!

To tackle this question, we will apply the Henderson-Hasselbach equation and solve for the molar ratio. It’s essential to obtain the pKa value for Acetic Acid, which is listed in reference tables as 4.76:

 pH=pKa + log ( \frac{[CH_3COONa]}{[CH_3COOH]} )

\frac{[CH_3COOH]}{[CH_3COONa}= 10^{(pH-pKa)^{-1}}=10^{(4-4,76)^{-1}}=5,75

Thus, the mole ratio of CH₃COOH to CH₃COONa is 5.75

Wishing you a wonderful day!

5 0
1 month ago
A chemist combined chloroform (CHCl3) and acetone (C3H6O) to create a solution where the mole fraction of chloroform is 0.187. T
KiRa [2933]

Answer:

\large \boxed{\text{c = 2.50 mol/L; b = 3.96 mol/kg }}

Explanation:

1. Molar concentration

Designate chloroform as C and acetone as A.

The molar concentration for C is derived from Moles of C per Litres of solution.

(a) Moles of C

We are assuming there are 0.187 moles of C.

This resolves that step.

(b) Litres of solution

Next, identify 0.813 moles of A.

(i) Mass of each component

\text{Mass of C} = \text{0.187 mol C} \times \dfrac{\text{119.38 g C}}{\text{1 mol C}} = \text{22.32 g C}\\\\\text{Mass of A} = \text{0.813 mol A} \times \dfrac{\text{58.08 g A}}{\text{1 mol A}} = \text{47.22 g A}

(ii) Volume of each component

\text{Vol. of C} = \text{22.32 g C} \times \dfrac{\text{1 mL C}}{\text{1.48 g C}} = \text{15.08 mL C}\\\\\text{Vol. of A} = \text{47.22 g A} \times \dfrac{\text{1 mL A}}{\text{0.791 g A}} = \text{59.70 mL A}

(iii) Volume of solution

Assuming mixing doesn't alter the total volume.

V = 15.08 mL + 59.70 mL = 74.78 mL

(c) Molar concentration of C

c = \dfrac{\text{0.187 mol}}{\text{0.07478 L}} = \textbf{2.50 mol/L }\\\\\text{ The molar concentration of chloroform is $\large \boxed{\textbf{2.50 mol/L}}$}

2. Molal concentration of C

Molal concentration is calculated as moles of solute per kilograms of solvent.

Total moles of C = 0.187 mol.

Mass of A = 47.22 g = 0.047 22 kg.

\text{b} = \dfrac{\text{0.187 mol}}{\text{0.047 22 kg}} = \textbf{3.96 mol/kg }\\\\\text{The molal concentration of chloroform is $\large \boxed{\textbf{3.96 mol/kg}}$}

4 0
1 month ago
During photosynthesis, sunlight shining on a plant is absorbed. Through several chemical reactions, the plant produces sugar, a
KiRa [2933]
The transformation involves converting thermal energy into chemical energy. Sugar is rich in chemical potential energy, which explains why it serves as an energy source for living organisms. Photosynthesis utilizes sunlight to transform carbon dioxide and water into sugar and oxygen, effectively changing the thermal energy from light into the chemical energy stored in sugar.

I hope this clarifies things. If you have any questions, feel free to ask.
4 0
8 days ago
Read 2 more answers
"solid potassium iodide decomposes into iodine gas and solid potassium. Write a a balanced chemical equation for this reaction"
Alekssandra [3086]


Now, construct a balanced equation:

2KI (s) ----\ \textgreater \ 2K(s) + I_2 (g)

I_2 exists in its gaseous form as a diatomic molecule.
3 0
1 month ago
A 0.784 g sample of magnesium is added to a 250 ml flask and dissolved in 150 ml of water. magnesium hydroxide obtained from the
Anarel [2989]

Although multiple values are given, our focus is on HCl.

<span>We have 215 mL (0.215 L) of 0.300 M HCl fully consumed in the reaction. It's important to recall that the number of moles is found by multiplying volume by molarity:</span>

 

moles = 0.215 L × 0.300 M

<span>moles = 0.0645 moles of HCl</span>

4 0
1 month ago
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