Answer:
- The density of ethanol measures 0.80 g/ml.
Explanation:
The density of water is known to be 1 g/ml, indicating that 158 g of water occupies a volume of 158 ml.
d = m/v = 258/258 = 1 g/ml
This implies the volume will remain the same for ethanol.
hence, the density of ethanol = 127/158 = 0.80 g/ml
Answer:
She will likely notice an increase in tire pressure.
Explanation:
According to the ideal gas law, pressure is directly related to temperature. Therefore, as temperature rises, so does pressure:
PV = nRT (Where P denotes pressure, V is volume, n represents moles, R is the ideal gas constant, and T signifies temperature).
Temperature indicates the average kinetic energy among the gas molecules. Thus, when the temperature goes up, the kinetic energy increases accordingly, leading gas molecules to speed up and collide more frequently with each other and with the tire walls. These impacts are more forceful due to the increased speed.
Consequently, the pressure escalates because it results from the collisions of gas molecules against the tire’s walls.
The question is incomplete,the complete question:
Determine the molality of a 10.0% (by weight) solution of hydrochloric acid in water:
a) 0.274 m
b) 2.74 m
c) 3.05 m
d) 4.33 m
e) the solution's density is necessary for calculations
Answer:
The molality for a 10.0% (by weight) hydrochloric acid solution is 3.05 mol/kg.
Explanation:
The solution is a 10.0% (by weight) hydrochloric acid mix.
This means there are 10 grams of HCl in 100 grams of the solution.
Amount of HCl = 10 g
Total mass of solution = 100 g
Total mass of solution = Mass of solute + Mass of solvent
Mass of solvent (water) = 100 g - 10 g = 90 g
Calculate moles of HCl = 
Mass of water converted to kilograms = 0.090 kg
Molality = 
<strongTherefore, the molality of a 10.0% (by weight) hydrochloric acid solution is 3.05 mol/kg.
Answer:
Joe correctly mixed the solution.
Explanation:
When evaluating both procedures, it's evident that both Jennifer and Joe weighed the same amount of potassium phosphate, which isn’t the variable here.
The difference is that Jennifer added the solid to 1.0 liters of water, resulting in a final volume greater than 1.0 L, thus her concentration will be lower than 1.0 M.
Joe's solution has a final volume of 1.0 L, which is why his preparation is accurate.
Answer:
B.
Explanation:
Elemental analysis reveals the precise percentage make-up of each component in the compound sample. Here, we have two distinct compounds, both containing copper and oxygen. However, the specific amounts of copper and oxygen in these compounds remain unknown.
An elemental composition will clarify this aspect and aid in determining the chemical formula for each compound, since the percentage of each element is now understood.
