The ether layer will consist of aniline and toluene following the extraction process. Explanation: Solvent extraction separates compounds based on their solubilities in two distinct immiscible liquids; typically, one being water and the other, an organic solvent like ether in this instance. PhCO₂H (benzoic acid) interacts with NaOH, resulting in a highly soluble benzoate ion in water yet poorly soluble in ether, thus it remains in the aqueous layer. Conversely, PhNH₂ (aniline) dissolves well in organic solvents such as ether while having minimal or no solubility in water; PhCH₃ (toluene) possesses solubility in ether whilst being insoluble in water. Hence, post-extraction, the ether layer encompasses aniline and toluene.
Answer:
See below for details
Explanation:
The attached graph illustrates that the x-axis represents time in seconds (s) while the y-axis represents depth in feet (ft). A positive depth indicates a location above water, whereas a negative depth refers to a position below water.
According to the graph, the coordinate (5, -8) indicates that the diver has reached her maximum depth after 5 seconds, meaning she was located 8 feet beneath the water's surface at that time. After that, she begins to swim upward.
Answer:
The empirical formula is: C₂H₃O
Explanation:
The empirical formula, often referred to as the “minimum formula,” provides the simplest way to represent a chemical compound, illustrating both the present elements and their minimum integer ratios in terms of atoms.
The mass percentage composition indicates the proportion by mass of each element in a compound.
Using 100 g of the compound as a reference, the percentage can be expressed in grams. Thus, presuming 100 g of the compound consists of 53.46 g of C, 6.98 g of H, and 39.56 g of O.
Considering the molecular masses of each component, one can derive the number of relative atoms for each element:
C: 
H:
O:
Subsequently, divide each value by the smallest one:
C: 
H:
O:
Approximating decimals to the nearest integer gives:
C: 2
H: 3
O: 1
Therefore the empirical formula is: C₂H₃O
