Response:
A=0.199
Clarification:
We know that
Mass of spring=m=450 g=
Where 1 kg=1000 g
Frequency of oscillation=

Energy for oscillation is 0.51 J
To determine the amplitude of oscillations.
Energy for oscillator=
Where
=Angular frequency
A=Amplitude

Using the formula



Therefore, the amplitude of oscillation=A=0.199
Explanation:
It is stated that,
Area of square coil, 
Length of one side of the square, L = 0.02 m
Number of coils, N = 10000
Consistent magnetic field, B = 1.5 T
Velocity, v = 100 m/s
An electromotive force is produced in the coil calculated as:


E = 30000 V
Breakdown voltage of air, 
Let d be the distance between the ends of the coil wires that can still produce a spark. Therefore,
Electric field, 

d = 0.075 m
Thus, this forms the final answer.
Answer:
The potential energy tied to the charge diminishes.
The electric field performs negative work on the charge.
Explanation:
Answer:
The mass will be 4.437 kg
Explanation:
The force constant k is given as 7 N/m
The time period of oscillation T is 5 sec
Thus, angular frequency 
It is known that angular frequency is computed via


Squaring both sides gives us

The mass equals 4.437 kg
J(r) = Br. We know that the area of a small segment, dA, is represented as 2 π dr. Thus, I = J A and dI = J dA. Plugging in the values gives us dI = B r. 2 π dr which simplifies to dI= 2π Br² dr. Now, integrating the above equation: Given that B= 2.35 x 10⁵ A/m³, with r₁ = 2 mm and r₂ equal to 2 + 0.0115 mm, or 2.0115 mm.