The volumes are 200cm3 and 0.0002m3
Answer:
Explanation:
Amount of gold deposited = 0.5 g
Gold's molar mass = 197 g/mol
Time duration, t = 6 hours
= 6 × 3600
= 12600 s
Calculation of moles: mass/molar mass
= 0.5/197
= 0.00254 mole
Assuming
Au --> Au+ + e-
Faraday's constant = 9.65 x 10^4 C mol-1
Charge, Q = 96500 × 0.00254
= 244.924 C
Relation: Q = I × t
Thus, I = 244.924/12600
= 0.011 A
= 11.34 mA.
1950 g This is the result of lead being spread out in kilograms