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satela
1 month ago
12

Select the areas that would receive snowfall because of the lake effect.

Physics
1 answer:
Keith_Richards [3.2K]1 month ago
8 0

Result:

- Grand Marais

- Two Harbors

- Duluth

Explanation:

The locations likely to receive snowfall due to lake effect include Grand Marais, Two Harbors, and Duluth. These areas are situated directly along the shores of Lake Superior, one of the world’s largest lakes. Its substantial water volume significantly influences the local climate, generating a lot of humidity in the air and considerable evaporation, both of which lead to cloud formation and, when temperatures drop adequately, result in significant snowfall rather than rain.

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When you apply the torque equation ∑τ = 0 to an object in equilibrium, the axis about which torques are calculated:
Softa [3030]

Answer:

option D.

Explanation:

The correct choice is option D.

For an object in equilibrium, the torque measured at any point will be zero.

An object is deemed to be in equilibrium when the net moment acting on it equals zero.

If the object experiences a net moment not equal to zero, it will rotate and will not remain stable.

3 0
2 months ago
Sully is riding a snowmobile on a flat, snow-covered surface with a constant velocity of 10 meters/second. The total mass of the
inna [3103]
Result: 168N

The calculation shows 16 - 10 equals 6
and 6 divided by 10 equals 0.6
. Therefore, F equals 280 multiplied by 0.6 equals 168.
7 0
1 month ago
Read 2 more answers
The muzzle velocity of a gun is the velocity of the bullet when it leaves the barrel. The muzzle velocity of one rifle with a sh
Keith_Richards [3271]

Answer: small barrel gun

Explanation:

It is noted that short barrel guns have a higher muzzle velocity for bullets compared to longer barrel guns.

Acceleration is determined by the change in velocity with respect to time.

a=\dfrac{\Delta v}{\Delta t}

For short barrel guns, the bullet reaches its muzzle velocity more quickly, leading to greater acceleration than that of bullets from long barrel guns.

7 0
2 months ago
Calculate the buoyant force in air on a kilogram of titanium (whose density is about 4.5 grams per cubic centimeter). compare wi
ValentinkaMS [3465]
1) The buoyant force acting on an object submerged in a fluid can be described as:
B=d_f V_d g
where d_f indicates the fluid's density, V_d represents the volume of the fluid displaced, and g=9.81~m/s^2 signifies the gravitational acceleration.

2) To determine the volume of the displaced fluid, we note that the titanium object is entirely submerged in the fluid (air), thus this volume matches the volume of 1 Kg of titanium, which has a density of d=4.5~g/cm^3 = 4.5\cdot10^3~Kg/m^3. Using the correlation between density, volume, and mass, we derive
V_d= \frac{m}{d}= \frac{1~Kg}{4.5\cdot10^3Kg/m^3}=2.22\cdot10^{-4}~m^3

3) We can now revisit the equation in step 1) to compute the buoyant force. Given that the air density is d_f = 1~Kg/m^3, this provides us with
B=d_f V_d g=1~Kg/m^3 \cdot 2.22\cdot10^{-4}~m^3 \cdot 9.81~m/s^2=2.22\cdot10^{-3}~N

4) The weight of 1 Kg of titanium is:
W=mg=1~Kg \cdot 9.81~m/s^2=9.81~N
Therefore, the buoyant force is negligible when compared to the weight.
7 0
2 months ago
A car traveling at 30 m/s runs out of gas while traveling up a 10 slope. how far up the hill what coast before starting to roll
Yuliya22 [3333]

Answer:

264.7 m

Explanation:

The force exerted on the vehicle as it moves up the incline corresponds to the weight component that aligns with the slope, hence:

F=-mg sin \theta

where

m denotes the vehicle's mass

g = 9.8 m/s² represents gravitational acceleration

\theta=10^{\circ}

and the negative sign indicates the force acts against the vehicle's direction of movement

Thus, the vehicle's acceleration is calculated as:

a=\frac{F}{m}=-gsin \theta=-9.8 sin 10^{\circ}=-1.7 m/s^2

To determine the distance the vehicle ascended, we can apply the equation:

v^2-u^2 = 2ad

where

v = 0 is the vehicle's final speed

u = 30 m/s signifies the initial speed

g = -1.7 m/s² stands for the acceleration

d is the distance traveled

By solving for d,

d=\frac{v^2-u^2}{2a}=\frac{0-30^2}{2(-1.7)}=264.7 m

3 0
2 months ago
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