Answer:
CH4
Explanation:
The ideal behavior of gases generally depends on the strength of intermolecular forces between gas molecules and whether polar bonds are present.
In the case of CCl4, polar bonds exist along with the more electronegative chlorine atom, leading to stronger intermolecular forces at 400K, as opposed to CH4 which contains only non-polar bonds.
Thus, at 400K, CH4 behaves more like an ideal gas compared to CCl4.
To determine the least degree of precision, we must base it on the mass of 4.05 kg or two decimal places. Thus, we add 0.56795 kg (0.57 kg) and 0.1001 kg (0.1 kg), resulting in a total of 4.72 kg.
<span>Conversely, to find the greatest degree of precision, we convert 4.05 kg into grams, which gives us 4050 g. Therefore, summing 4050 g with 567.95 g and 100.1 g yields 4718.05 grams, which rounds to 4718 g.</span>
Explanation:
Initial moles of ethanoic acid = 0.020 mol
At equilibrium, half of the ethanoic acid molecules have reacted.
Thus, moles of ethanoic acid reacted = 0.020 mol * (50% / 100%)
= 0.010 mol
Moles of ethanoic acid remaining = 0.020 mol - 0.010 mol = 0.010 mol
The moles of product 
gas formed are determined as follows:
0.010 mol CH3COOH * (1 mol / 2 mol CH3COOH)
= 0.005 mol
Consequently, the total moles of gas present in the vessel at equilibrium are 0.010 mol CH3COOH and 0.005 mol
Total gas moles at equilibrium = 0.010 mol + 0.005 mol = 0.015 mol
Next, let’s determine the pressure:
0.020 mol of gas has a pressure of 0.74 atm; so under the same conditions, we find the pressure exerted by 0.015 mol of gas:
P1/n1 = P2/n2
P2 = P1*(n2 / n1)
= 0.74 atm * (0.015 mol / 0.020 mol)
= 0.555 atm
Answer:
9.69g
Explanation:
To find the needed outcome, we first need to determine the number of moles of N2 present in 7.744L of the gas.
1 mole of gas takes up 22.4L at STP.
Thus, X moles of nitrogen gas (N2) will fill 7.744L, meaning
X moles of N2 = 7.744/22.4 = 0.346 moles
Next, we will convert 0.346 moles of N2 to grams to achieve the result sought. The calculation goes as follows:
Molar Mass of N2 = 2x14 = 28g/mol
Number of moles N2 = 0.346 moles
Find the mass of N2 =?
Mass = number of moles × molar mass
Mass of N2 = 0.346 × 28
Mass of N2 = 9.69g
Hence, 7.744L of N2 consists of 9.69g of N2
