2NaOH + H₂SO₄ = Na₂SO₄ + 2H₂O
v(H₂SO₄)=0.25 L
c(H₂SO₄)=2.00 mol/L
v(NaOH)=2.00 L
n(H₂SO₄)=c(H₂SO₄)v(H₂SO₄)
n(NaOH)=2n(H₂SO₄)=2c(H₂SO₄)v(H₂SO₄)
c(NaOH)=n(NaOH)/v(NaOH)=2c(H₂SO₄)v(H₂SO₄)/v(NaOH)
c(NaOH)=2*2.00*0.25/2.00=0.5 mol/L
the concentration of the NaOH solution is 0.5 mol/L
Answer:
evaporated
Explanation:
Once the solution evaporates, only salt will remain, as the sole other component in the solution is water.
Explanation:
It is established that 1 gram is equivalent to 1000 milligrams. We can express this mathematically in the following way.
or 
Thus, to convert grams to milligrams, we simply multiply the number by 1000. Conversely, for converting milligrams back to grams, we divide by 1000.
Answer:
Explanation:
The oxidation state corresponds to the charge of each atomic ion. An increase indicates oxidation of the element while a decrease reflects reduction of the element.
2AgCl+Zn⟶2Ag+ZnCl2
Zinc undergoes oxidation, while Ag experiences reduction.
Ag⁺ changes to Ag (oxidation state decreases), thus Ag is reduced.
Zn alters to Zn⁺² (oxidation state increases), hence Zn is oxidized.
4NH₃+3O₂⟶2N₂+6H₂O
The oxidation state of nitrogen in ammonia is -3
whereas it is zero in elemental nitrogen.
An increase in the oxidation state indicates nitrogen is oxidized.
The oxidation state of oxygen is zero when in molecular oxygen and -2 when in water. Therefore, the oxidation state decreases, indicating oxidation is reduced.
Fe₂O₃+2Al⟶Al₂O₃+2Fe
The oxidation state of Fe in Fe₂O₃ is +3, switching to zero in Fe, so iron is reduced.
Aluminum's oxidation state is zero in Al, rising to +3 in Al₂O₃, indicating it is oxidized.
We need to calculate the volume of Gold, assuming its mass matches that of copper.
Given information:
Density of Copper = 8.96 g/ml.
Volume of Copper = 141 ml.
Mass of Gold = Mass of Copper.
Density of Gold = 19.3 g/ml.
To find copper's mass, we use the density equation:
Density = mass/volume.
To find mass of copper:
Mass of copper = Density of Copper * Volume of Copper.
Mass of copper = 8.96 g/ml * 141 ml = 1263.36 g.
Thus,
Mass of gold = Mass of copper = 1263.36 g.
Now, using the density formula for gold to get its volume:
Volume of gold = Mass of gold / Density of gold.
Volume of gold = 1263.36 g / 19.3 g/ml = 65.46 mL.
Consequently, the volume of gold required to match the mass of copper is 65.46 mL.
