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7 days ago

A Gas OCCUPIES 525ML AT A PRESSURE OF 85.0 kPa WHAT WOULD THE VOLUME OF THE GAS BE AT THE PRESSURE OF 65.0 kPa

2 answers:

8 0

Boyle's law pertaining to ideal gases states that the volume of a gas relates inversely to its pressure when temperature is constant. According to this principle, the relationship between pressure and volume can be expressed as:

$PV=Constant$

This implies:

$P_{1}V_{1}=P_{2}V_{2}$

Utilizing this equation enables us to determine the volume of gas given a specific pressure:

P₁=Initial pressure

V₁=Initial volume

P₂=Final pressure

V₂= Final volume

In this case, the initial pressure P₁ is noted as 85.0 kPa.

The initial volume V₁ is provided as 525 mL.

The final pressure P₂ is recorded as 65.0 kPa.

$P_{1}V_{1}=P_{2}V_{2}$

Thus,

V_{2}=85×525÷65

=686 mL

Consequently, the gas volume will amount to 686 mL.

Alekssandra [992]7 days ago

4 0

The response is 45.0, although I am uncertain.

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In how many grams of water should 25.31 g of potassium nitrate (kno3) be dissolved to prepare a 0.1982 m solution?

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Solution:

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Thus,

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Answer:

Please review the following responses

Explanation:

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2) 100. mL of NaCl solution at 3.00 M (3 M)

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4) The concentrations of beakers 1 and 5 are identical (1.5M)

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59 g -------------- 1 mol

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x = 19.5 x 1/59 = 0.33 mol

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Answer:

The correct answer is "Speed".

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Answer:

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