Answer:
The snowball's speed after the impact is 3 m/s
Explanation:
Given the following:
mass of each ball
m₁ = 0.4 Kg
m₂ = 0.6 Kg
initial speed of both balls = v₁ = 15 m/s
Speed of 1 Kg mass post-collision =?
Applying conservation of momentum
m₁ v₁ - m₂ v₁ = (m₁+m₂) V
A negative velocity indicates that the second ball moves in the opposite direction.
0.4 x 15 - 0.6 x 15 = (1) V
Therefore,
V = - 3 m/s
Consequently,
The snowball's speed following the collision is 3 m/s
The magnetic field is calculated to be -6.137 × T. Explanation: Given the radio wave wavelength of λ = 0.3 m and an intensity of I = 45 W/m² at times t = 0 and t = 1.5 ns, we determine Bz at the origin. We use the intensity formula relating to the electric field, which incorporates the known intensity of 45, the speed of light c = 3 × m/s², and ∈o as 8.85 × C²/N.m², leading us to E = 184.15. Consequently, applying the equations, we find B = -6.137 × T at the z-axis.
The gravitational force acting on the elevator is 4500N. Explanation: The parameters provided indicate that the force exerted by the elevator is F = 4500 N. The elevator does not accelerate. According to Newton's third law, the force exerted by the cable matches the gravitational force on the elevator, which represents its weight (W), and the elevator's motion stands as follows: F = W + (Mass of elevator × Acceleration of elevator). Therefore, F = W + (Mass of elevator × 0) = W, which leads us to F = 4500 N = W. The net force on the elevator can be expressed as F - W = 0, confirming that the gravitational force on the elevator equals W = 4500N.
V - wind speed;
53° - 35° = 18°
v² = 55² + 40² - 2 · 55 · 40 · cos 18°
v² = 3025 + 1600 - 2 · 55 · 40 · 0.951
v² = 440.6
v = √440.6
v = 20.99 ≈ 21 m/s
Conclusion: The wind speed calculates to 21 m/s.
<span>Part b) Find your horizontal distance from the window (answer: 1.5 m)
Part c) Calculate the speed of the ball upon catching it (answer: 8.2 m/s)
I'm confused about what "42 degrees below the horizontal" means. Could someone provide guidance on how to approach this?</span>
