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andrey2020
12 days ago
6

Sketch the circuit labeling the meter and bulb as two separate resistors connected in parallel to the voltage source. Then show

mathematically that if the meter’s internal resistance is 1000 times higher than the bulb’s resistance, the current in the meter is 1000 times less than through the bulb. This shows why measuring voltage with a multimeter does not affect the circuit.

Physics
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The δe of a system that releases 12.4 j of heat and does 4.2 j of work on the surroundings is __________ j.
Yuliya22 [3333]

For this issue, the answer is clarified as the system takes in energy (+). The surroundings contribute 84 KJ of work. Whenever a system is receiving work from its surroundings, the value will be positive. Therefore, it sums to 12.4 KJ + 4.2 = 16.6 KJ.

5 0
2 months ago
A car drives 215 km east and then 45 km north. What is the magnitude of the car’s displacement? Round your answer to the nearest
Ostrovityanka [3204]
The Pythagorean Theorem can be utilized here: Imagine a car navigating through traffic—when it turns left to travel north, a right angle of 90 degrees is formed. However, the displacement is always the shortest distance connecting the origin and the endpoint, which forms a triangle in this scenario. In a right triangle, the Pythagorean theorem applies: 215^2+45^2=c^2; therefore, v=√(215^2+45^2).
8 0
1 month ago
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You are in a hot-air balloon that, relative to the ground, has a veloc- ity of 6.0 m/s in a direction due east. You see a hawk m
Softa [3030]

Answer:

6.32 m/s at an angle of 18.43° northeast

Explanation:

We represent the hawk's velocity as follows:

v_{Hawk}=v_{balloon}+v_{HawkRelativetoBalloon}=6 x+2 y

We set east as the positive x direction and north as the positive y direction. Hence, the magnitude is simply calculated using the square root of the squared components:

|v_{hawk}|=\sqrt[]{6^2+2^2}=\sqrt{40}≈6.32 m/s

And the angle in relation to east is given by:

arctan(\frac{2}{6} )=18.43 \°

8 0
2 months ago
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