At time 
, the ball's horizontal and vertical velocities can be represented as
However, since the ball is thrown horizontally, we have 
. The horizontal and vertical positions at time are
The ball travels a distance of 22 m horizontally from the throw point, thus
With this, we determine that the time for the ball to reach the ground is
When it touches down, 
and
The greatest mass that can hang without submerging is 2.93 kg. The provided details are as follows: sphere diameter = 20 cm, hence the radius r = 10 cm = 0.10 m. The density of the Styrofoam sphere is 300 kg/m³. The sphere's volume calculates to 4.18 * 10⁻³ m³. Mass M = Density * Volume results in (300)(4.18 * 10⁻³ m³) = 1.25 kg. The displaced water mass is computed as volume * water density, yielding 4.18 * 10⁻³ m³ * 1000 = 4.18 kg. The additional mass the sphere can hold is the difference between the two mass calculations: 4.18 kg - 1.25 kg = 2.93 kg.
To find the mass using a weight of 1.4 N:
1.4/9.8 = 0.1428 kg
The momentum is calculated as 0.1428 multiplied by 44.7, which is 6.38 kgm/s.
Given
m1(mass of red bumper): 225 Kg
m2 (mass of blue bumper): 180 Kg
m3(mass of green bumper): 150 Kg
v1 (velocity of red bumper): 3.0 m/s
v2 (final velocity of the combined bumpers):?
The principle of momentum conservation indicates that the momentum before impacts equals the momentum after impacts. This can be represented mathematically as:
Pa= Pb
Pa symbolizes the momentum prior to collision and Pb refers to momentum after collision.
Applying this principle to the aforementioned scenario results in:
Momentum pre-collision= momentum post-collision.
Momentum pre-collision = (m1+m2) x v1 =(225+180)x 3 = 1215 Kgm/s
Momentum post-collision = (m1+m2+m3) x v2 =(225+180+150)x v2
=555v2
We now know that Momentum pre-collision equals momentum post-collision.
<presulting in="">
1215 = 555 v2
v2 = 2.188 m/s
Consequently, the final velocity of the combined bumper cars is 2.188 m/s
</presulting>
Answer:
A.
Explanation:
Storing the linens in the closet will prevent them from becoming dirty or contaminated.
