Answer:
Speeds of 1.83 m/s and 6.83 m/s
Explanation:
Based on the law of conservation of momentum,
where m represents mass, 
is the initial speed before impact, 
and 
are the velocities of the impacted object after the collision and of the originally stationary object after the impact.
Thus, 
After the collision, the kinetic energy doubles, therefore:
Substituting the initial velocity of 5 m/s provides the equation needed to proceed.
We know that leads to 
Using the quadratic formula leads us to solve for the speeds after the explosion, specifically where a=2, b=-10, and c=-25. 
By substituting the values, the solution yields results for the speeds of the blocks, which are ultimately 1.83 m/s and 6.83 m/s.
Answer:
W = 294 J
Explanation:
provided,
mass of the projectile = 2 Kg
horizontal displacement = 20 m
vertical displacement = 15 m
work performed by the gravitational force =?
the work done by gravitational force only accounts for vertical motion.
force due to gravity = m g
= 2 x 9.8 = 19.6 N
work is equal to force x displacement
W = F x s
W = 19.6 x 15
W = 294 J
Answer:
The tension in the string when the speed increased is 134.53 N
Explanation:
Given;
Tension in the string, T = 120 N
initial speed of the transverse wave, v₁ = 170 m/s
final speed of the transverse wave, v₂ = 180 m/s
The wave speed is expressed as;
where;
μ represents mass per unit length
The new tension T₂ will be computed as;
Consequently, the tension in the string when the speed was increased is 134.53 N
Answer:
50.2 cm
Explanation:
We have the following data:
Height, h=3.5 m
Initial horizontal velocity, 
Time, t=0.32 s
We need to determine how far the ball is from the ground after 0.32 s.
Initial vertical velocity, 
Where 
