Answer:
To break a single I-I bond, the wavelength of light required is 7.92 × 10⁻⁷ m
Explanation:
The energy needed to break one mole of iodine-iodine single bonds is 151 KJ
The energy necessary to rupture one iodine-iodine bond is calculated as (151 KJ/mol) / 6.02 × 10²³/mol = 2.51 × 10⁻²² KJ
or
2.51 × 10⁻¹⁹ J
Formula:
E = hc / λ
Where h is Planck's constant = 6.626 × 10⁻³⁴ js
c is the speed of light = 3 × 10⁸ m/s
λ
= wavelength
Solution:
E = hc / λ
λ = hc / E
λ = (6.626 × 10⁻³⁴ js × 3 × 10⁸ m/s ) / 2.51 × 10⁻¹⁹ J
λ = 19.878 × 10⁻²⁶ j.m / 2.51 × 10⁻¹⁹ J
λ = 7.92 × 10⁻⁷ m
Answer: The correct option is (1).
Explanation:
Group 16 is the third-from-last column in the periodic table and is known as the oxygen family.
Members of this group include oxygen, sulfur, selenium, tellurium, and polonium.
Elements in Group 16 have 6 valence electrons in their outermost shell.
The electronic configuration of sulfur is 
.
Because sulfur belongs to Group 16, it has 6 valence electrons.
Explanation:
Filtration serves as a method of separation where solid particles that are suspended in a liquid are isolated by passing the mixture through filter paper's pores. This process ensures that the solid particles accumulate on the filter paper and the liquid flows out through the filter paper's pores.
The ordered sequence of the steps provided is:
- Measure and fold the filter paper.
- Insert the filter paper into the funnel, then position the funnel above the Erlenmeyer flask.
- Let the solid/liquid mixture pass through the filter.
- Rinse the filter paper that holds the mixture with water.
- Measure the weight of the dry filter paper along with the copper.
The solution to your inquiry is: c = a + b - d. In the chemical equation aA + bB → cC + dD, c may take any value from 1 to however many are needed for the equation to maintain its balance. For instance, if we consider c + d = a + b, we can express c as a + b - d. If we assign values a = 1; b = 3, and d = 2, then c equals 1 + 3 - 2, resulting in c = 2, and so forth.
