The dipole moment u can be calculated using the formula
U = rq
Where u represents the dipole moment
R indicates the bond length
Q = 1.6x10-19 C
Hence,
R = u/q
R = (0.797 d) ( 3.34x10^-30 Cm/ 1
d) /( 1.6x10^-19 C)(0.118)
R = 1.41x10^-10 m
<span>R = 141 pm</span>
Answer:
H+(aq) + OH-(aq) ⟶ H2O(l)
Explanation:
Step 1: The balanced equation can be presented as
HCN(aq) + KOH(aq) ⟶ H2O(l) + KCN(aq)
H+(aq) + CN-(aq) + K+(aq) + OH-(aq) ⟶ H2O(l) + K+(aq) + CN-(aq)
Step 2: The net ionic equation is formed by removing the spectator ions — those that appear on both sides of the equation — leading us to the final representation:
H+(aq) + OH-(aq) ⟶ H2O(l)
To determine the least degree of precision, we must base it on the mass of 4.05 kg or two decimal places. Thus, we add 0.56795 kg (0.57 kg) and 0.1001 kg (0.1 kg), resulting in a total of 4.72 kg.
<span>Conversely, to find the greatest degree of precision, we convert 4.05 kg into grams, which gives us 4050 g. Therefore, summing 4050 g with 567.95 g and 100.1 g yields 4718.05 grams, which rounds to 4718 g.</span>
They overcomplicated things with lots of words. Your initial equation deals with the revenue. I’ll denote tacos as x and burritos as y.
The first equation would be 3x + 7.25y = 595, given that you already have the prices but need the quantities. The second equation will reflect that double the burritos were sold compared to tacos, expressed as y = x + 2.
Hope this clarifies things. If you need further explanation, I can elaborate more.
Answer:
C. connecting an active metal to designate the pipe as the cathode in an electrochemical cell.
Explanation:
Cathodic protection involves a method to manage the accelerated corrosion of a metal surface by designating it as the cathode within an electrochemical cell. This is accomplished by attaching the protected metal to a more sacrificial metal, which acts as the anode.
This method helps to preserve the metal by introducing a highly reactive metal that serves as the anode, supplying free electrons. By adding these free electrons, the active metal gives up its ions, protecting the less reactive steel from corrosion.
