The new pressure of the gas is calculated to be 40.7 kPa. Using the principle that P1 • V1 = P2 • V2, we can set 98.8 kPa (P1) multiplied by 21.7 mL (V1) equal to P2 (unknown pressure) multiplied by 52.7 mL (V2). To isolate P2, we rearrange the equation to P2 = (98.8 kPa • 21.7 mL) / 52.7 mL, resulting in P2 equal to 40.7 kPa.
We need to calculate the volume of Gold, assuming its mass matches that of copper.
Given information:
Density of Copper = 8.96 g/ml.
Volume of Copper = 141 ml.
Mass of Gold = Mass of Copper.
Density of Gold = 19.3 g/ml.
To find copper's mass, we use the density equation:
Density = mass/volume.
To find mass of copper:
Mass of copper = Density of Copper * Volume of Copper.
Mass of copper = 8.96 g/ml * 141 ml = 1263.36 g.
Thus,
Mass of gold = Mass of copper = 1263.36 g.
Now, using the density formula for gold to get its volume:
Volume of gold = Mass of gold / Density of gold.
Volume of gold = 1263.36 g / 19.3 g/ml = 65.46 mL.
Consequently, the volume of gold required to match the mass of copper is 65.46 mL.
The mass of hydrogen is 16.0 oz. To convert 16.0 oz of hydrogen into pounds, we utilize the conversion factor 1 lb = 16 oz. Next, we convert pounds to grams using the factors 1 kg = 2.2 lb and 1 kg = 1000 g. The heat of combustion for hydrogen is 142 J/g, and we will calculate the heat produced by combusting 16.0 oz.
<span>To determine the specific heat of a solid sample, I’d begin by measuring the mass of the solid. Then, I would prepare a sufficient quantity of water at room temperature to fully submerge the solid. This water would go in an insulated container. I'd then heat the solid to a known temperature. Next, I’d record both the temperature of the solid and the water. After that, I'd submerge the heated sample in the water, allowing them to reach thermal equilibrium. I would then note this final equilibrium temperature.
The temperature difference between the heated sample and the equilibrium state indicates the change in temperature of the solid. Given the known mass, initial temperature of the water, and the equilibrium temperature, I can calculate the energy transferred from the solid to the water.
With the mass of the sample, the change in temperature of the solid, and the transferred energy, I have enough information to find the specific heat of the solid sample</span>
The mass calculated for the copper piece is 290 grams. The formula for mass is given by mass = density × volume, where the density of copper is 8.96 grams per mL. The volume of the copper piece, determined by the increase in volume, equals 137 mL - 105 mL = 32 mL. Multiplying the volume by the density gives us the mass of copper: mass = 8.96 g/mL × 32 mL = 286.72 grams. Since the volume is presented with two significant figures, rounding the mass to two significant figures results in 290 grams.
