A water tank can hold 1 m3 of water. When it’s empty, how much liters is needed to refill it?

Explanation:

Elements provided:

  F, Sr, P, Ca, O, Br, Rb, Sb, Li, S

Elements sharing similar reactivity belong to the same group in the periodic table, indicating that those in the same column exhibit comparable reactivity. Here are the identified groupings:

  Li and Rb are alkali metals in group 1

  Ca and Sr are alkaline earth metals in group 2

  F and Br are halogens in group 7

  O and S belong to group 6

 P and Sb are classified in group 5 of the periodic table

Thus, these classifications illustrate elements with the same chemical characteristics.

Answer:

The nichrome wire has contaminants.

The sample solution might be tainted.

Explanation:

If the nichrome wire is contaminated, sodium impurities could be causing the yellow flame. The wire is initially placed in the flame without the sample to check for such impurities.

The testing solution could also be contaminated, causing it to display a color different from the anticipated shade of the test ion.

Response:

9.9 ml of 0.200M NH₄OH(aq)

Reasoning:

3NH₄OH(Iaq) + FeCl₃(aq) => NH₄Cl(aq) + Fe(OH)₃(s)

What volume in ml of 0.200M NH₄OH(aq) will fully react with 12ml of 0.550M FeCl₃(aq)?

1 x Molarity of NH₄OH x Volume of NH₄OH Solution(L) = 2 x Molarity of FeCl₃ x Volume of FeCl₃ Solution

1(0.200M)(Volume of NH₄OH Soln) = 3(0.550M)(0.012L)

=> Volume of NH₄OH Soln = 3(0.550M)(0.012L)/1(0.200M) = 0.0099 Liters = 9.9 milliliters

Answer: Pentane C5H12

Explanation:

The boiling point is defined as the temperature at which a liquid's vapor pressure matches the external pressure, causing the liquid to turn into vapor.

This compound is likely Pentane, represented as C5H12, since its boiling point falls between that of Butane, with the formula C4H10, and Hexane, with the formula C6H14.

Answer:

Calcium phosphate has the formula Ca3(PO4)2, which has a molar mass of 310 grams per mole.

For 2.3*10^-4 moles, we calculate 2.3*10^-4 * 310, resulting in 713*10^-4 grams, or 71.3 milligrams.

If the formula is accurate but the compound's name is incorrect, simply replace 310 with 278, yielding 639.4*10^-4 grams, equivalently 63.94 milligrams.