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Andrej
2 months ago
11

A horizontal, cylindrical, tank, with hemispherical ends, is used to store liquid chlorine at 10 bar. The vessel is 4 m internal

diameter and 20 m long. Estimate the minimum wall thickness required to resist this pressure, for the cylindrical section and the heads. Take the design pressure as 12 bar and the allowable design stress for the material as 110 MN/m2.
Engineering
1 answer:
Daniel [329]2 months ago
3 0

Answer: 0.021818m = 2.18x10^-²m

Explanation: According to Laplace's principle

Design pressure equals 12 bar or 1200000N/m².

T denotes the wall thickness.

Design stress is 110Mn/m² equating to 110,000,000N/m².

Radius is calculated as diameter/2 = 4/2 = 2m.

Design stress equates to hoop stress: Pr/t, where p indicates internal pressure, r signifies radius, and t represents wall thickness.

<pas stated="" by="" the="" laplace="" equation.="">

110,000,000 = 1,200,000 x 2/t.

Solving for t gives t = 2,400,000/110,000,000.

Thus, t = 0.021818m.

Ultimately, t = 2.18x10^-2m.

</pas>
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3 months ago
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Consider a rectangular fin that is used to cool a motorcycle engine. The fin is 0.15m long and at a temperature of 250C, while t
Kisachek [356]

Answer:

q' = 5826 W/m

Explanation:

Given:-

- The length of the fin in question, L = 0.15 m

- The fin's surface temperature, Ts = 250°C

- The velocity of free stream air, U = 80 km/h

- The air temperature, Ta = 27°C

- The flow is parallel over both sides of the fin, assuming turbulent flow conditions throughout.

Find:-

What is the heat removal rate per unit width of the fin?

Solution:-

- Steady state conditions are assumed, along with negligible radiation and turbulent flow conditions.

- From Table A-4, we gather air properties (T = 412 K, P = 1 atm ):

    Dynamic viscosity, v = 27.85 * 10^-6 m²/s  

    Thermal conductivity, k = 0.0346 W / m.K

    Prandtl number Pr = 0.69

- Compute the Nusselt Number (Nu) corresponding to - turbulent conditions - using the relevant relationship as follows:

                          Nu = 0.037*Re_L^\frac{4}{5} * Pr^\frac{1}{3}

Where,    Re_L: Average Reynolds number for the entire length of fin:

                          Re_L = \frac{U*L}{v} \\\\Re_L = \frac{80*\frac{1000}{3600} * 0.15}{27.85*10^-^6} \\\\Re_L = 119688.80909

Consequently,

                         

Nu = 0.037*(119688.80909)^\frac{4}{5} * 0.69^\frac{1}{3}\\\\Nu = 378

- The convective heat transfer coefficient (h) can now be derived from:

                          h = \frac{k*Nu}{L} \\\\h = \frac{0.0346*378}{0.15} \\\\h = 87 \frac{W}{m^2K}

- The heat loss rate q' per unit width can be established using the convection heat transfer formula and should be multiplied by (x2) since the airflow is present on both sides of the fin:

                          q' = 2*[h*L*(T_s - T_a)]\\\\q' = 2*[87*0.15*(250 - 27)]\\\\q' = 5826\frac{W}{m}

- Ultimately, the heat loss per unit width from the rectangular fin is q' = 5826 W/m

- The thermal loss per unit width (q') attributed to radiation:

                  q' = 2*a*T_s^4*L

Where, a signifies the Stefan-Boltzmann constant = 5.67*10^-8

                  q' = 2*5.67*10^-^8*(523)^4*0.15\\\\q' = 1273 \frac{W}{m}

- It is observed that radiation losses are not insignificant, accounting for 20% of thermal loss by convection. As the emissivity (e) of the fin is unspecified, this value is dismissed from the calculations as it pertains to the provided information.

7 0
2 months ago
Retype the below code. Fix the indentation as necessary to make the program work. if 'New York' in temperatures: if temperatures
Daniel [329]

Answer: Below is the correctly formatted code:

if 'New York' in temperatures:

if temperatures['New York'] > 90:

   print('The city is melting!')

else:

   print('The temperature in New York is', temperatures['New York'])

else:

   print('The temperature in New York is unknown.')

Explanation:

This is the entire program:

temperatures = {

   'Seattle': 56.5,

   'New York': 105,

   'Kansas City': 81.9,

   'Los Angeles': 76.5

}

if 'New York' in temperatures:

if temperatures['New York'] > 90:

   print('The city is melting!')

else:

   print('The temperature in New York is', temperatures['New York'])

else:

   print('The temperature in New York is unknown.')

The output will be:

The city is melting!

This program mainly comprises nested if statements. The first check determines if 'New York' exists within the temperature data. When confirmed, it moves to another if statement to see if New York's temperature exceeds 90. If true, it outputs the message, "The city is melting!". If false, it presents the actual temperature of New York. If neither condition is satisfied, it defaults to showing that the temperature is unknown. Given that New York's temperature is 105, the output reflects that the city is melting!

Proper indentation is crucial in Python, as it distinguishes code blocks without needing brackets, enhancing readability. Observe how the nested if statements are structured within the outer if statement. The else statements align appropriately beneath their respective if declarations, and print statements follow the necessary indentation.

4 0
3 months ago
Write multiple if statements. If car_year is 1969 or earlier, print "Few safety features." If 1970 or later, print "Probably has
alex41 [359]

Answer:

The following includes the explanation, code, and resulting outputs.

C++ Code:

#include <iostream>

using namespace std;

int main()

{

int year;

cout<<"Enter the car model year."<<endl;

cin>>year;

if (year<=1969)

{

cout<<"Few safety features."<<endl;

}

else if (year>=1970 && year<1989)

{

cout<<"Probably has seat belts."<<endl;

}

else if (year>=1990 && year<1999)

{

cout<<"Probably has antilock brakes."<<endl;

}

else if (year>=2000)

{

cout<<"Probably has airbags."<<endl;

}

return 0;

}

Explanation:

The challenge involved displaying feature messages for a car based on its model year.

Logical conditions were integrated into the coding. The implementation has been verified with multiple inputs producing the expected results.

Output:

Enter the car model year.

1961

Few safety features.

Enter the car model year.

1975

Probably has seat belts.

Enter the car model year.

1994

Probably has antilock brakes.

Enter the car model year.

2005

Probably has airbags.

5 0
2 months ago
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