Dissolving NaOH(s) in water is exothermic. Two calorimetry experiments are set up. Experiment 1: 2 g of NaOH are dissolved in 10
1 answer:
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Answer: The correct option is 3.
Explanation: Radioisotopes that emit alpha-particles are termed alpha-emitters. These isotopes undergo alpha-decay.
Those radioisotopes that emit beta-particles are called beta-emitters. They undergo beta-minus decay, in which a neutron converts to a proton and an electron.
Isotopes that emit positrons are known as positron-emitters, undergoing beta-plus decay where a proton becomes a neutron.
From the options given,
Option 1: All three isotopes undergo beta-minus decay.
Option 2: Cs-137 and Tc-99 undergo beta-minus decay.
Fr-220 undergoes alpha-decay.
Option 3: Kr-85 undergoes beta-minus decay.
Ne-19 undergoes positron decay.
Rn-222 undergoes alpha decay.
Option 4: All three isotopes undergo beta-minus decay processes.
Therefore, the correct choice is 3.
Answer:
Complete Question:
Equimolar quantities of CH3OH(l) and C2H5OH(l) are placed in separate 2.0 L containers that have been evacuated beforehand. Pressure gauges are attached to each container, and the temperature is maintained at 300 K. In both containers, liquid is consistently visible at the bottom. The varying pressure within the vessel that contains CH3OH(l) is illustrated below.
In comparison to the equilibrium vapor pressure of CH3OH(l) at 300 K, the equilibrium vapor pressure of C2H5OH(l) at 300 K is
ANSWER : lower, since the London dispersion forces among C2H5OH molecules surpass those among CH3OH molecules.
Explanation:
To clarify the answer provided, let’s begin by defining some concepts.
The London dispersion force is the least strong type of intermolecular force. It is a temporary force that arises when the electron arrangement in two neighboring atoms creates transient dipoles.
The vapor pressure of a liquid reflects the equilibrium pressure of its vapor above the liquid (or solid); specifically, it represents the pressure associated with the evaporation of a liquid (or solid) in a sealed environment above the substance.
The pressure will be lower due to the stronger London dispersion forces acting between C2H5OH molecules compared to those between CH3OH molecules. This implies that when intermolecular forces are stronger, they intensify the interactions binding the substance together, thereby reducing the liquid's vapor pressure at any given temperature and making it more difficult to vaporize the substance.
Note: The London dispersion force for C2H5OH is more substantial than for CH3OH because C2H5OH has more electrons than CH3OH.
