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alexdok
2 months ago
13

Dissolving NaOH(s) in water is exothermic. Two calorimetry experiments are set up. Experiment 1: 2 g of NaOH are dissolved in 10

0 mL of water Experiment 2: 4 g of NaOH are dissolved in 200 mL of water Which of the following statements is true?a. both temperature changes will be the sameb. the second temeprature change will be approximately twice the firstc. the second temperature change will be approximately four times the firstd. the second temperature change will be approximately one-half of the firste. the second temperature change will be approximately one-fourth the first
Chemistry
1 answer:
eduard [2.7K]2 months ago
5 0

Answer:

a. the temperature changes will be identical

Explanation:

Dissolving sodium hydroxide (NaOH) in water is an exothermic process, with the heat released calculated using:

Q = m×C×ΔT

Where Q indicates the heat released, m refers to the mass of the solution, C is the specific heat, and ΔH stands for temperature change.

The specific heat of both solutions remains the same (because both are the same solutions). Specific heat = C.

m denotes the mass of the solutions: 102g for experiment 1 and 204g for experiment 2.

The heat released, Q: If 2g releases X heat, then 4g releases 2X.

Thus, the temperature change for each experiment is:

Experiment 1:

X / 102C = ΔT

Experiment 2:

2X / 204C = ΔT

X / 102C = ΔT

Indicating that,

a. the temperature changes will be identical

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