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ziro4ka
3 months ago
6

A bus is designed to draw its power from a rotating flywheel that is brought up to 3000 rpm by an electric motor. The flywheel i

s a solid cylinder of mass 2000 kg and diameter 1 m. If the bus requires an average power of 20 kilowatts, how long will the flywheel rotate?
620 s

830 s

980 s

1,200 s

2,500 s
Physics
1 answer:
Yuliya22 [3.3K]3 months ago
3 0

To tackle this problem, we will use the concept of rotational kinetic energy. After determining this energy, we will find the time based on the power definition, which indicates how energy changes over time. Let's begin with the formula for the kinetic energy of a rotating flywheel:

E_r = \frac{1}{2} I\omega^2

Where

I = moment of inertia

\omega = Angular velocity

In this scenario, we have:

\omega = 3000\frac{rev}{min}(\frac{2\pi rad}{1rev})(\frac{1min}{60s})

\omega = 314.159rad/s

Substituting the moment of inertia values for this object yields:

E_r = \frac{1}{2} (\frac{MR^2}{2})\omega^2

E_r = \frac{1}{2} (\frac{2000(0.5)^2}{2})(314.159)^2

E_r = 1.233698*10^7J

The average power expression is given by:

P = \frac{E_r}{\Delta t}

\Delta t = \frac{E_r}{P}

\Delta t = \frac{1.233698*10^7}{20*10^3}

\Delta t = 616.8s \approx 620s

Hence, the correct conclusion is 620 seconds.

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Rohit placed a pencil perpendicular to principal axis in front of a converging
serg [3582]

Response:

45cm

Clarification:

A converging mirror is generally termed a concave mirror. The focal length and the image distance for a concave mirror are both expressed as positive values.

Using the mirror formula to derive the object distance;

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

Where f denotes the focal length, u indicates the object distance, and v represents the image distance.

Given f = 30cm, and v = 2u (The formed image is double the size of the pencil)

Plugging these values into the formula to solve for u yields;

\frac{1}{30} = \frac{1}{u} + \frac{1}{2u}\\\frac{1}{30} = \frac{2+1}{2u}\\\frac{1}{30} = \frac{3}{2u}\\

By cross-multiplying, we obtain;

2u = 90

Dividing both sides by 2;

2u/2 = 90/2

u = 45cm

The object's distance from the mirror measures 45cm

3 0
4 months ago
Digital bits on a 12.0-cm diameter audio CD are encoded along an outward spiraling path that starts at radius R1=2.5cm and finis
Sav [3153]

Answer:

The overall length of the spiral, designated as L, is calculated to be 5378.01 m

Explanation:

Provided information:

Inner radius R1=2.5 cm

and outer radius R2= 5.8 cm.

The thickness of the spiral winding is (d) =1.6 \mu m = 1.6x 10^{-6} m

The total length of the spiral can be computed as

= \frac{(Area\ of\ the\ spiraing\ portion\ on\ the\ disk)}{d}

=\frac{\pi *(R_2)^2 - \pi*(R_1)^2}{d}

=\frac{\pi *(0.058)^2 - \pi*(0.025)^2}{1.6*10^{-6}}

= 5378.01 m

5 0
3 months ago
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