The force experienced by the electron is 4.0×10⁻¹⁷ N.
Response:
A protractor to gauge the angle between the inclined plane and the horizontal
Explanation:
The student must elevate the free end of the adjustable inclined plane until the object just begins to slide and record the angle at that precise moment. At this juncture, the frictional force is balanced by the weight component aligned with the incline. That is:

and 
Consequently, the coefficient of static friction can be entirely established by calculating the tangent of the angle formed by the incline with the horizontal.

For this, the sole additional tool needed is a protractor for angle measurement.
Answer:
The outcome of adding 999mm to 100m is 101m.
Explanation:
That's my belief.
Answer:
Induced EMF is 2 x 10⁻³ volts
Explanation:
B = strength of the magnetic field aligning with the loop's axis = 1 T
= area change rate of the loop = 20 cm²/s = 20 x 10⁻⁴ m²
θ = the angle formed by the magnetic field and area vector = 0
E = the induced EMF across the loop
EMF can be calculated using the formula
E = B
E = (1) (20 x 10⁻⁴ )
E = 2 x 10⁻³ volts
E = 2 mV
Answer:
11109.825 N
Explanation:
Provided Information:
mass = m = 1510 kg
initial acceleration (a) = 0.75g (where g = 9.81 m/s²)
Using the formula F=ma
= (1510)*(0.75*9.81)
= 11109.825 N