A 30.0 mL sample of hydrogen gas (H2) is collected over water at 20.00∘C and has a total pressure of 700.0 torr. The partial pre

Utilize the ideal gas law:

n = PV / RT

P = 100kPa = 100 x 1000 x (9.8 x 10^{-6}) = 0.98 atm
Convert kPa to atm, where 1 Pa = 9.8 x 10^{-6} atm.
T = 293 K
V = 6.8 L
R = 1/12
Substituting all values leads to:
n = 0.272

Answer:

a)

b) 1657 €

Explanation:

Hola,

a) En esta cuestión analizaremos el millón de litros de agua anualmente, dado que este dato nos permite calcular el calor necesario para calentar dicha cantidad, considerando que la densidad del agua es de 1 kg/L:

A continuación, utilizamos la entalpía de combustión del metano para determinar la cantidad en kilogramos necesaria, ya que la energía calórica perdida por el metano es equivalente a la energía obtenida por el agua:

b) En este supuesto, tenemos que, bajo condiciones normales de 1 bar y 273 K, el precio de 1 metro cúbico de metano es 0,45 €, lo que nos permite calcular las moles de metano en esas condiciones:

En consecuencia, los kilogramos de metano que se obtienen por 0,45 € son:

Finalmente, usando regla de tres:

0.715 kg ⇒ 0.45 €

2630 kg ⇒ X

X = (2630 kg x 0.45 €) / 0.715 kg

X = 1657 €

Regards.

Answer:

The new gas pressure within the chamber registers at 1,093.75 mmHg

Explanation:

The Gay-Lussac Law establishes a relationship between a gas's pressure and temperature when volume remains constant. This principle asserts that gas pressure is directly tied to its temperature: as temperature increases, pressure rises, and conversely, as temperature falls, pressure also diminishes. Therefore, the Gay-Lussac law can be depicted mathematically as:

Given an initial and final state of gas, we can apply the following formula:

In this scenario:

• P1= 1560 mmHg
• T1= 445 K
• P2=?
• T2= 312 K

<psubstituting:>

Calculating:

P2=1,093.75 mmHg

The new gas pressure inside the chamber is 1,093.75 mmHg

</psubstituting:>

Answer:

The correct choice is: option A.

Justification:

To address this inquiry, we need to evaluate the total number of electrons each orbital can accommodate.

  Orbital                         Number of electrons

   s                                   2

   p                                  6

   d                                 10

   f                                  14

Provided options:

A. 1s² 2s² 2p⁶ 3s²                 This configuration is valid as it aligns with the permitted number of electrons in each orbital and follows the correct sequence.

B. 1s² 2s² 2p⁶ 3s² 3d⁴          This configuration is not accurate because

                                         3d⁴ should follow 3p.

C. 1s² 2s² 2d¹⁰ 2p³                This is incorrect since 2d¹⁰ is not a valid orbital.

D. 1s² 2s^s 2p³ 2d¹⁰            This option contains two errors; s as an exponent does not exist, and 2d¹⁰ is also an invalid description.

The quantity is 6.074 X 10¹⁸ molecules. To calculate the molecular weight (MM) of the compound C₂₇H₄₆O, we use the formula: 27*(MM of C) + 46*(MM of H) + (MM of O). This leads to: 27*(12.0107) + 46* (1.00784) + (15.999) = 324.2889 + 46.36064 + 15.999 = 386.64854 g. The molar mass of any compound indicates the number of molecules found in one mole, which is 6.022 X 10²³ (Avogadro's number). So, if 386.64854 g of C₂₇H₄₆O consists of 6.022 X 10²³ cholesterol molecules, we can determine how many molecules are found in a deposit of 3.9mg or 0.0039g of C₂₇H₄₆O by using the unitary method. Number of molecules = 6.074 X 10¹⁸ molecules.