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victus00
1 month ago
5

How many liters of cane juice is needed to supply 5g sucrose if cane juice contains 12% sucrose

Chemistry
1 answer:
alisha [2.8K]1 month ago
6 0

Given parameters:

Mass of sucrose  = 5g

Density of sucrose  = 1.12g/mL

Percentage of sucrose per liter of cane juice  = 12%

Unknown:

Volume of cane juice required =?

We need to understand the relationship between volume and density. Density represents mass per unit volume.

Mathematically;

                Density  = \frac{mass}{volume}

Now, calculate the volume of sucrose;

                  1.12g/mL = \frac{5}{Volume}

       Volume  = \frac{5}{1.12}    =  4.46mL   = 4.46 x 10⁻³L since 1000mL  = 1L

Since 12% of one liter of cane juice is sucrose,  

                    12% of  x  liter of cane juice  = 4.46 x 10⁻³L

                   Volume of cane juice  = 4.46 x 10⁻³ x \frac{100}{12}   = 0.037L

Volume of cane juice needed is  0.037L

   

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93.2 mL of a 2.03 M potassium fluoride (KF) solution
alisha [2865]

Response:

1.98 M

Clarification:

Provided data

  • Starting volume (V₁): 93.2 mL
  • Starting concentration (C₁): 2.03 M
  • Water volume added: 3.92 L

Step 1: Convert V₁ to liters

Using the relationship 1 L = 1000 mL.

93.2mL \times \frac{1L}{1000mL} = 0.0932 L

Step 2: Calculate the final volume (V₂)

The final volume is the total of the initial volume and the added water volume.

V_2 = 0.0932L + 3.92 L = 4.01L

Step 3: Calculate the final concentration (C₂)

Utilizing the dilution rule.

C_1 \times V_1 = C_2 \times V_2\\C_2 = \frac{C_1 \times V_1}{V_2} = \frac{2.03 M \times 3.92L}{4.01L} = 1.98 M

3 0
13 days ago
Read 2 more answers
mixture or pure substance: 1.blood 2.dyes 3.self-raising flour 4.muesli 5.copper wire 6.distilled water 7.table salt 8.milk 9.br
alisha [2865]

Answer: Mixture: Blood, Self raising flour,muesli,dyes, milk, tea, air, bronze

Pure substance: Copper wire, distilled water, table salt, oxygen.

Explanation:

A mixture is a substance composed of two or more compounds which are chemically independent and keep their individual chemical properties.

Examples: Blood, Self raising flour,muesli,dyes, milk, tea, air, bronze

A pure substance is defined as something with a uniform and constant composition and is called a pure substance.

Examples: Copper wire, distilled water, table salt, oxygen.

5 0
22 days ago
A 1.0 mol sample of X(g) and a 1.0 mol sample of Q(g) are introduced into an evacuated, rigid 10.0 L container and allowed to re
castortr0y [2906]
At equilibrium, [R] = [Z] > [Q]. Explanation: In analyzing the equilibrium conditions, the provided reaction of X(g) + 2 Q(g) ⇄ R(g) + Z(g) establishes that at a temperature of 50ºC, the equilibrium constant Kc = 1.3 x 105. This indicates a scenario where the concentrations of the products greatly exceed those of the reactants.
6 0
14 days ago
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A chemist has 2.0 mol of methanol (CH3OH). The molar mass of methanol is 32.0 g/mol. What is the mass, in grams, of the sample?
castortr0y [2906]

Answer:

\boxed {\boxed {\sf D. \ 64 \ grams }}

Explanation:

We have a certain quantity of moles, and we need to determine the mass of the sample.

The molar mass of methanol is known to be 32.0 grams per mole. This value can be employed as a ratio.

\frac{32 \ g \ CH_3OH}{1 \ mol \ CH_3OH}

Next, we multiply by the specified number of moles, which is 2.0.

2.0 \ mol \ CH_3OH *\frac{32 \ g \ CH_3OH}{1 \ mol \ CH_3OH}

The moles of methanol will be canceled out.

2.0 \ *\frac{32 \ g \ CH_3OH}{1 }

The 1 in the denominator can be overlooked.

2.0 * 32 \ g\ CH_3OH

Now, perform the multiplication.

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Thus, the sample contains 64 grams of methanol.

3 0
1 month ago
The student collects the H2(g) produced by the reaction and measures its volume over water at 298 K after carefully equalizing t
KiRa [2853]

Answer:

The pressure of H₂(g) is 741 torr

Explanation:

We know:

The atmospheric pressure in the lab is measured at 765 torr

The vapor pressure of water is 24 torr

Using Dalton's Law of Partial Pressure:

P_{total} = P_{H_2}+P_{H_2O}

To isolate the pressure in the tube from H₂(g):

we have:

P_{H_2} = P_{total} - P_{H_2O}

= (765 - 24) torr

= 741 torr

Hence, the pressure of H₂(g) is 741 torr

4 0
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