The time period for any moon of Jupiter is described by the formula above, which also allows us to calculate Jupiter's mass. For part a, T is 1.77 days, which is equal to 152928 seconds. Applying the formula, we can derive the values needed. For part B, T equals 3.55 days or 306720 seconds, and repeating this with the necessary formula allows us to find the mass of Jupiter. For part c, T is 7.16 days, equating to 618624 seconds. Once again, using the earlier formula, we find Jupiter's mass. Finally, for PART D, T is noted to be 16.7 days or 1442880 seconds, and we can find the mass of Jupiter using the provided formula.
A left turn lane is designated for vehicles making left turns. Vehicles must completely enter this lane and wait for a clear path before proceeding with the turn. It is not permissible for a vehicle to be partially in and out of the lane, as this obstructs traffic and creates hazardous conditions.
Answer:
The mass will be 4.437 kg
Explanation:
The force constant k is given as 7 N/m
The time period of oscillation T is 5 sec
Thus, angular frequency 
It is known that angular frequency is computed via


Squaring both sides gives us

The mass equals 4.437 kg
Answer:

Explanation:
In this scenario, we determine the initial velocity as follows:

The final velocity in this instance can be expressed as:

It is noted that transitioning from 7m/s to 13m/s takes 8 seconds. We can apply a specific kinematic equation to find the acceleration for the first part of the journey:

Solved for acceleration, we find:

For the subsequent route, we assume constant acceleration and that the train continues for 16 seconds, beginning with an initial velocity of 13m/s from the previous segment, allowing us to calculate the final speed via the following formula:

Substituting into the equation yields:
