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Dahasolnce
19 days ago
12

An antibaryon composed of two antiup quarks

Physics
1 answer:
Maru [2.3K]19 days ago
5 0

Answer:

(2) −1 e

Explanation:

Quarks are the lightest among elementary particles, making up hadrons like protons and neutrons. Each quark carries a fractional charge.

Up, charm, and top quarks possess +\frac{2}{3} e charge, whereas down, strange, and bottom quarks have -\frac{1}{3}e charge.

Anti-up quarks, which are the antiparticles of up quarks, carry -\frac{2}{3}e charge.

Antidown quarks serve as the antiparticles of down quarks, possessing +\frac{1}{3}e charge.

An antibaryon consists of two anti-up quarks and one anti-down quark.

The overall charge of an antibaryon is:

2\times (-\frac{2}{3} e)+1\times (+\frac{1}{3})e=-1e

Therefore, the charge for the antibaryon is -1e.

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Ostrovityanka [2208]

The result is -15.625 m/s².


Acceleration signifies the alteration of velocity over a specified duration. It can be calculated with this formula:


a = \dfrac{vf-vi}{t}

Where:

vf = final velocity

vi = initial velocity

t = time

Let’s examine the information provided in your query:

Initially, the vehicle was traveling at 25 m/s before coming to a halt. Thus, it was in motion and subsequently ceased moving, indicating that the final velocity is 0 m/s.


However, we notice that the problem does not provide a time value. We need to determine the time taken from when it was in motion to when it reached the traffic light located 20 m away.


The time can be calculated using the kinematics equation:

d = \dfrac{vi+vf}{2} *t


We derive the equation by substituting the known values first.

20m = \dfrac{25m/s+0m/s}{2}(t)

20m = 12.5m/s{2}(t)

\dfrac{20m}{12.5m/s}=t
1.6s=t

The duration from when it was in motion until it stopped is 1.6s. Now we can utilize this in our acceleration calculation.


a = \dfrac{0m/s-25m/s}{1.6s}

a = \dfrac{-25m/s}{1.6s}

a = -15.625m/s^{2}


It is important to note that the acceleration is negative, indicating the vehicle slowed down.

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10 days ago
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Ostrovityanka [2208]

Answer:

Explanation:

According to the parameters provided,

mass of the clay lump, m₁ = 0.05 kg

initial velocity of the lump, u₁ = 12 m/s

mass of the cart, m₂ = 0.15 kg

initial speed of the cart, u₂ = 0

As the clay adheres to the cart, we have an inelastic collision scenario. Let v represent the combined speed of both the cart and lump post-collision. Given that momentum is conserved, we have:

m_1u_1+m_2u_2=(m_1+m_2)v

v=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}

v=\dfrac{0.05\ kg\times 12\ m/s+0}{0.05\ kg+0.15\ kg}

The resultant speed is v = 3 m/s.

Thus, the final speed of both cart and lump following the collision is 3 m/s. This concludes the solution.

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19 days ago
Why didn't the astronauts land on the moon 3.17 answers punchline?
kicyunya [2264]

Answer:

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Others claimed that the astronauts took off during daylight hours when the moon was not visible. There were also comments that indicated that 'astro' refers to stars rather than satellites, explaining why they did not land.

A few even noted that 'astro naut' sounds like 'naught,' meaning zero (0), as a possible reason for their failure to land.

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Keith_Richards [2263]
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V2 = Flow rate/A2 = 0.0013/0.0008 = 1.625 m/s
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At Point 1:
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V1 = Flow rate/A1 = 0.0013/0.0002 = 6.5 m/s
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I do not concur with her stance. The concept of planetary motion emerges from a collaborative effort involving Johannes Kepler and Sir Isaac Newton. I believe Tycho Brahe's role was minimal since it was really Kepler who made the significant discoveries.

(this is my original response that was accepted)
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