If the following elements were to form ions, they would attain the same number of electrons as which noble gas? As , Be , O , S
2 answers:
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Response:
of
can be found in 39.5 grams of
.
Clarification:
Atomic weights: P= 31, F= 19,
The molar mass equals 1 atomic weight of P + 5 atomic weights of
F= 31+5 × 19 = 31+95
=126 g/mole
The number of moles in 39.5 gm of
equals
=
=0.3134 moles
1 mole of any substance encompasses
0.3131 moles comprises 0.3134
Thus, of
can be found in 39.5 grams of
.
Result: 1.68 L of liquid nitrogen is generated during the gas liquefaction process.
Clarification:
This process involves transforming gaseous nitrogen into its liquid form.
The two states possess distinct densities, thus occupying varying volumes; however, the mass remains constant.
Step 1: Calculate the mass of nitrogen gas
Let’s determine the mass of nitrogen gas associated with 297 L.
The density formula is:
With a density of nitrogen gas at 4.566 g/L and a volume of 297 L, we can compute the mass of nitrogen gas as follows:
Using these values yields:
The mass of nitrogen gas calculates to be 1356 g.
Step 2: Derive the volume of liquid nitrogen from the mass obtained
The mass for liquid nitrogen remains the same.
With the density of liquid nitrogen at 809 g/L, we can substitute this into our formula to find the volume of liquid.
Therefore, the volume of liquid nitrogen is 1.68 L.