If the following elements were to form ions, they would attain the same number of electrons as which noble gas? As , Be , O , S

Question

Mekhanik

17 days ago

6

If the following elements were to form ions, they would attain the same number of electrons as which noble gas? As , Be , O , S

, Ca , Mg , Sr

Chemistry

2 answers:

Alekssandra [992] · Answer 1 · 2026-02-16T21:39:33+03:00

Answer;

As and Sr ------- [Kr]

Be ------------- [He]

O and Mg ------- [Ne]

S and Ca ------- [Ar]

Explanation

The Be+ ion has 2 electrons, matching He. The Mg2+ and O2− ions possess 10 electrons each, like Ne.
S2− and Ca2+ ions each have 18 electrons, the same as Ar. The As3− and Sr+ ions hold 36 electrons, paralleling Kr.
Elements gain or lose electrons to reach a stable electron configuration akin to that of noble gases.
When atoms lose electrons, they form positive ions (cations), and when they gain electrons, they form negative ions (anions).

Alekssandra [992] · Answer 2 · 2026-02-16T21:35:13+03:00

When forming ions, arsenic achieves the same electron count as krypton.

Berillium attains an electron configuration identical to helium upon ion formation.

Oxygen reaches the electron configuration of neon after it forms an ion.

Sulfur obtains the same number of electrons as argon when it becomes an ion.

Calcium attains argon's electron configuration upon ionization.

Magnesium gains the electron arrangement of neon after ion formation.

Strontium adopts krypton’s electron configuration as an ion.

Additional explanation:

Electron distribution within atoms follows specific principles:

1. Aufbau principle: Electrons occupy orbitals starting with the lowest energy level progressing upward.

2. Hund’s rule: Electrons singly occupy orbitals before pairing occurs.

3. Pauli’s exclusion principle: No two electrons in the same orbital can share identical quantum numbers; they must differ in spin.

Ions form through gaining or losing electrons, where anions result from electron gain and cations from electron loss.

Arsenic (atomic number 33) gains three electrons resulting in a configuration like krypton. Beryllium (4) loses two electrons to match helium's configuration. Oxygen (8) gains two electrons, matching neon's configuration. Sulfur (16) gains two electrons equaling argon's configuration. Calcium (20) loses two electrons, also reaching argon’s electron count. Magnesium (12) loses two electrons matching neon's configuration. Strontium (38) loses electrons to achieve krypton's electron arrangement.