The visual representation is displayed in the following image.
For calculations, consider 100 grams of the compound:
ω(Cl) = 85.5% ÷ 100%.
ω(Cl) = 0.855; signifying the mass percentage of chlorine in the compound.
m(Cl) = 0.855 · 100 g.
m(Cl) = 85.5 g; this represents the mass of chlorine.
m(C) = 100 g - 85.5 g.
m(C) = 14.5 g; indicating the mass of carbon.
n(Cl) = m(Cl) ÷ M(Cl).
n(Cl) = 85.5 g ÷ 35.45 g/mol.
n(Cl) = 2.41 mol; this is the quantity of chlorine.
n(C) = 14.5 g ÷ 12 g/mol.
n(C) = 1.21 mol; this is the quantity of carbon.
n(Cl): n(C) = 2.41 mol: 1.21 mol = 2: 1.
The compound in question is identified as dichlorocarbene CCl₂.
Answer: The right choice is (c) application of both a mobile phase and a stationary phase.
Explanation:
Chromatography: This refers to a technique for separating a mixture where the mixture is distributed between two phases at varying rates, one being stationary and the other moving.
Mobile phase: The component in which the mixture is dissolved is referred to as the mobile phase.
Stationary phase: This is an adsorbent medium that remains in place while a liquid or gas passes over its surface, thus remaining stationary.
Consequently, a key characteristic of any chromatography technique involves utilizing both a mobile and a stationary phase.
Answer:
In blood: Dispersed phase: blood cells; Dispersed medium: liquid plasma
In fruit jelly: Dispersed phase: fruit juice; Dispersed medium: pectin
Explanation:
The dispersed phase refers to the phase where colloidal particles are dispersed within another phase, known as the dispersion medium.
In blood, the tiny cells act as colloidal particles, forming the dispersed phase within the liquid medium identified as plasma.
Conversely, in fruit jelly, the fruit juice constitutes the dispersed phase while the solid pectin serves as the dispersed medium.
When two atoms with equal electronegativity bond together, they form nonpolar covalent bonds.
Your second statement mirrors the first; the second statement likely reads, "Bonds between two atoms with unequal electronegativity are termed polar covalent bonds."
Answer:
Explanation:
The oxidation state corresponds to the charge of each atomic ion. An increase indicates oxidation of the element while a decrease reflects reduction of the element.
2AgCl+Zn⟶2Ag+ZnCl2
Zinc undergoes oxidation, while Ag experiences reduction.
Ag⁺ changes to Ag (oxidation state decreases), thus Ag is reduced.
Zn alters to Zn⁺² (oxidation state increases), hence Zn is oxidized.
4NH₃+3O₂⟶2N₂+6H₂O
The oxidation state of nitrogen in ammonia is -3
whereas it is zero in elemental nitrogen.
An increase in the oxidation state indicates nitrogen is oxidized.
The oxidation state of oxygen is zero when in molecular oxygen and -2 when in water. Therefore, the oxidation state decreases, indicating oxidation is reduced.
Fe₂O₃+2Al⟶Al₂O₃+2Fe
The oxidation state of Fe in Fe₂O₃ is +3, switching to zero in Fe, so iron is reduced.
Aluminum's oxidation state is zero in Al, rising to +3 in Al₂O₃, indicating it is oxidized.
