Marie discovers boxes of elements in a storage room. The boxes do not say which elements they contain, but they do have informat

Answer: The molecular formula will be

Explanation:

When percentages are provided, we assume the total mass to be 100 grams.

Thus, the mass of each element corresponds to the specified percentage.

Mass of C= 70.6 g

Mass of H = 5.9 g

Mass of O = 23.5 g

Step 1: convert given masses to moles.

Moles of C =

Moles of H =

Moles of O =

Step 2: For determining the mole ratio, divide each molar amount by the smallest number of moles calculated.

For C =

For H =

For O =

The resulting ratio of C: H: O= 4: 4: 1

Hence, the empirical formula obtained is

The empirical weight is calculated as = 4(12)+4(1)+1(16)= 68g.

The molecular weight = 136 g/mole

Now the molecular formula needs to be obtained.

The molecular formula can be derived as=

Answer:

78.96 g of NaC2H3O2

Explanation:

The following information is provided:

• The solution's volume is 350 mL
• The solution's molarity is 2.75 M
• The molar mass of NaC2H3O2 is 82.04 g/mol

We need to find the mass of the solute:

First, we calculate the number of moles:

Moles = Molarity × Volume

Thus;

Moles of solute = 2.75 M × 0.350 L

                        = 0.9625 moles

Next, we find the mass:

Mass = Moles × Molar mass

        = 0.9625 moles × 82.04 g/mol

        = 78.9635 g

      = 78.96 g

Therefore, the amount of NaC2H3O2 required is 78.96 g

Response:

Aluminum

Clarification: