If you stand next to a wall on a frictionless skateboard and push the wall with a force of 40n, how hard does the wall push on y

Answer:

17 m/s south

Explanation:

Mass of the dog = 10 kg

Mass of skateboard = 2 kg

v = Combined velocity = 2 m/s

Velocity of the dog = 1 m/s

Velocity of skateboard

In this scenario, linear momentum is conserved

The speed of the skateboard post-dog jump will be 17 m/s south, considering north as the positive direction

Response:

Once it has crossed, the locomotive requires 17.6 seconds to achieve a speed of 32 m/s.

Details:

  The locomotive's acceleration is 1.6

  The duration taken to pass the crossing is 2.4 seconds.

  We can apply the motion equation, v = u + at, where v represents final velocity, u indicates initial velocity, a denotes acceleration, and t signifies time.

  When the speed reaches 32 m/s, we have v = 32 m/s, u = 0 m/s, and a= 1.6 .

   32 = 0 + 1.6 * t

    t = 20 seconds.

  Therefore, the locomotive attains a speed of 32 m/s after 20 seconds, and it passes the crossing in 2.4 seconds.

Thus, after clearing the crossing, it takes an additional 17.6 seconds to reach the speed of 32 m/s.

Answer:

Explanation:

According to the principle of energy conservation

all kinetic energy will change into thermal energy to increase its temperature

Next, divide both sides by the object's mass

the resulting temperature change is expressed as

Answer:

The energy delivered is E = 0.18 J

Explanation:

Given,

Battery voltage, V = 9 V

Charge in the circuit, Q = 20 mC

                                        = 20 x 10³ C

Energy supplied in the circuit can be computed as

E = Q V

E = 20 x 10⁻³ x 9

E =  180 x 10⁻³

E equals 0.18 J.

The energy delivered in the circuit is therefore E = 0.18 J